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Marina CMI [18]
2 years ago
10

Her wollemolecules are callede Blood cells, Proteinsmembrance remain in the blood​

Physics
1 answer:
astra-53 [7]2 years ago
6 0

Answer:

Other peripheral membrane proteins of red blood cells include actin, ankyrin ... proteins to be characterized, its precise function remains unknown. ... This protein​, originally known as band 3, is the anion ... and small polar molecules (in the case of E. coli, with molecular weights up to 600).

Explanation:

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A spring suspended vertically is 11.9 cm long. When you suspend a 37 g weight from the spring, at rest, the spring is 21.5 cm lo
Naddika [18.5K]

Answer:

Time period of oscillations is 0.62 s

Explanation:

Due to suspension of weight the change in the length of the spring is given as

\Delta L = L_f - L_i

\Delta L = 21.5 - 11.9 = 9.6 cm

now we know that spring is stretched due to its weight so at equilibrium the force due to weight is counter balanced by the spring force

mg = kx

0.037 (9.81) = k(0.096)

k = 3.78 N/m

Now the period of oscillation of spring is given as

T = 2\pi \sqrt{\frac{m}{k}}

Now plug in all values in it

T = 2\pi \sqrt{\frac{0.037}{3.78}}

T = 0.62 s

5 0
3 years ago
QUICK PLEASE! WILL GIVE BRAINLIEST!
Crank

Answer:

hi!

Explanation:

i think the answer is x=0m , y=0,55m

7 0
3 years ago
Read 2 more answers
A space vehicle accelerates uniformly from 85 m/s at t = 0 to 164 m/s at t = 10.0 s .How far did it move between t = 2.0 s and t
creativ13 [48]

First, we have a change in the velocity from 85 to 164 m/s in 10 sec.

Then, we calculate the <u>acceleration </u>as:

a=\frac{v_{f}-v_{i} }{t} =\frac{164-85}{10}=7.9 m/s^2

Hence we need to calculate the velocity of the space vehicle at t = 2 sec using the first equation of motion:

v_{f}=v_{i}+at=85+7.9*2=100.8m/s

Then, using the second equation of motion to calculate the distance:

d=v_{i}  t+\frac{1}{2}at^2

d=100.8*2+\frac{1}{2}*7.9*(2)^2=217.4m

5 0
3 years ago
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According to a college survey, 22% of all students work full time. find the mean for the number of 3) students who work full tim
attashe74 [19]

Assuming that the students worldwide are being considered, because of the extremely large population, this can be considered as a binomial distribution. A normal distribution is used most usually as a fair approximation of the binomial. The mean is the expectation, therefore:<span>
E[x] = np = (16)(0.22) = 3.52 
<span>μ = 3.52 </span></span>

3 0
3 years ago
What is the energy range (in joules) of photons of wavelength 410 nm to 750 nm ? Express your answers using two significant figu
andreyandreev [35.5K]

Answer:

4.9 x 10^-19 J, 2.7 x 10^-19 J

Explanation:

first wavelength, λ1 = 410 nm = 410 x 10^-9 m

Second wavelength, λ2 = 750 nm = 750 x 10^-9 m

The relation between the energy and the wavelength is given by

E = h c / λ

Where, h is the Plank's constant and c be the velocity of light.

h = 6.63 x 10^-34 Js

c = 3 x 10^8 m/s

So, energy correspond to first wavelength

E1 = (6.63 x 10^-34 x 3 x 10^8) / (410 x 10^-9) = 4.85 x 10^-19 J

E1 = 4.9 x 10^-19 J

So, energy correspond to second wavelength

E2 = (6.63 x 10^-34 x 3 x 10^8) / (750 x 10^-9) = 2.652 x 10^-19 J

E2 = 2.7 x 10^-19 J

4 0
3 years ago
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