What is the mass of a cart that accelerates at 3.0 m/s if a 0.5 N force is applied?
1 answer:
The mass of the cart is 0.167 kg
Explanation:
We can solve the problem by using Newton's second law, which states that the net force applied to an object is equal to the product between its mass and its acceleration:
where
F is the net force acting on an object
m is its mass
a is its acceleration
For the cart in this problem, we have
F = 0.5 N is the net force applied
is the acceleration
Substituting, we find the mass:
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The temperature of the gas is 41.3 °C.
Answer:
The temperature of the gas is 41.3 °C.
Explanation:
So on combining the Boyle's and Charles law, we get the ideal law of gas that is PV=nRT. Here P is the pressure, V is the volume, n is the number of moles, R is gas constant and T is the temperature. The SI unit of pressure is atm. So we need to convert 1 Pa to 1 atm, that is 1 Pa = 9.86923× atm. Thus, 171000 Pa = 1.6876 atm.
We know that the gas constant R = 0.0821 atmLMol–¹K-¹. Then the volume of the gas is given as 50 L and moles are given as 3.27 moles.
Then substituting all the values in ideal gas equation ,we get
1.6876×50=3.27×0.0821×T
Temperature =
So the temperature is obtained to be 314.3 K. As 0°C = 273 K,
Then 314.3 K = 314.3-273 °C=41.3 °C.
Thus, the temperature is 41.3 °C.