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Monica [59]
3 years ago
9

Find the moment in relation to the force of point O of the force P applied to the end A of the knee lever. The value of the forc

e P = 100N. (Correct answer = 51 Nm)

Physics
1 answer:
sattari [20]3 years ago
6 0

Answer:

2=2

Explanation:

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observe the figure given carefully volume of water in each vessel is shown arrange them in order of decreasing pressure at the b
mihalych1998 [28]

Answer:

See the explanation below

Explanation:

The pressure is defined as the product of the density of the liquid by the gravitational acceleration by the height, and can be easily calculated by means of the following equation.

 P=Ro*g*h

where:

Ro = density of the fluid [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation [m]

In this way we can understand that the greater pressure is achieved by means of the height of the liquid, that is, as long as the fluid has more height, greater pressure will be achieved at the bottom.

Therefore in order of decreasing will be  

The largest pressure with the largest height of the liquid, container B. The next is obtained with container D, the next with container A and the lowest pressure with container C.  

The pressure decreases as we go from the container B - D - A - C

5 0
3 years ago
In the woman's mouth if
Tpy6a [65]

Answer:

hi mate,

interesting question, first of all the pressure is determined by using the following formula:

Pg = p * G * h  

where p is the density of the liquid, G is the gravity and h is the height difference, in you case you have:

p = 1015 kg/m3

G = 9.8m/s2

h = 0.085 m  

insert these values into the equation above:

Pg = 1015 kg/m3 * 9.8m/s2 * 0.085 m = 849.81 kg·m-1·s-2 or 849.81 pascal

hope it helps, :-)

please mark me as brainliest

7 0
3 years ago
Your teacher (175kg) and the lab (15kg) are 2m apart. What is the gravitational force between them? Draw a FBD, and label
Pachacha [2.7K]
The gravitational force between two objects is given by
F=G \frac{m_1 m_2 }{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

In this problem, m_1 = 175 kg, m_2 =15 kg and r=2 m, therefore the gravitational force between the two objects is
F=(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2}) \frac{(175 kg)(15 kg)}{(2m)^2}=4.38 \cdot10^{-8} N
7 0
3 years ago
Three balls, with masses of 3m,2m and m, are fastened to a massless rod of length L. The rotational inertias about the ledt
Oduvanchick [21]

I = MR^2

The Attempt at a Solution:::

I total = (3M)(0)^2 + (2M)(L/2)^2 + (M)(L)^2

I total = 3ML^2/2

It says the answer is 3ML^2/4 though.

⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔

mark it as brainliest.... ✌✌✌

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Humans protect themselves from natural disasters by all of the following except
jeyben [28]
I'm pretty sure it's sunscreen
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