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Lilit [14]
2 years ago
12

Need help with this question.... Next to each Formula, write the number of atoms of each element found in one unit of the compou

nd.
These are the Compounds below:
1. potassium iodide, KI
2. sodium sulfide, NA2S
3. silicon dioxide, SiO2
4. carbonic acid, H2CO3
Chemistry
1 answer:
Andrew [12]2 years ago
7 0

Answer:

The number of atoms present in one unit of the following compounds is:

a). Potassium Iodide , KI = 2

b).Sodium Sulfide, Na_{2}S = 3

c). Silicon Dioxide , SiO_{2} = 3

d). Carbonic Acid ,H_{2}CO_{3} = 6

Explanation:

Atomicity : It is defined as the number of atoms that are present in a given molecule/compound.

Atom : The smallest unit of matter is called atom. For e.g O is atom of oxygen but O_{2} is not an atom , it is molecule of oxygen .

O_{2} molecule has 2 atoms of Oxygen

Similarly  Na , K , Fe are atoms but O_{2} ,CO_{2} ,N_{2},H_{2}  are molecules

a).Potassium Iodide

KI = 1 atom of K + 1 atom of I

Total atoms = 2

b) Sodium Sulfide

Na_{2}S = 2 atoms of Na + 1 atom of S

Total atoms = 3

c) Silicon Dioxide

SiO_{2} = 1 atom of Si + 2 atoms of O

Total atoms = 3

d) Carbonic Acid

H_{2}CO_{3} = 2 atom of H + 1 atom of C + 3 atom of O

= 2+1+3

Total atoms = 6

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Taking into account the definition of average atomic mass and isotopes of an element, the information that you need is the masses of its isotopes and their percent abundances.

Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number Z.

But in the nucleus of each element it is also possible to find neutrons, whose number can vary. The atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus.

The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.

The atomic mass of an element is the weighted average mass of its natural isotopes. Therefore, the atomic mass of an element is not a whole number.

The weighted average means that not all isotopes have the same percentage.

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Explanation:

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Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample
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According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

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n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=2:2=1:1

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol

The ratio of number of moles of carbon and oxygen will be:

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The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.


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