Question

Need help with this question.... Next to each Formula, write the number of atoms of each element found in one unit of the compound.
These are the Compounds below:
1. potassium iodide, KI
2. sodium sulfide, NA2S
3. silicon dioxide, SiO2
4. carbonic acid, H2CO3

Answer 1

Answer:

The number of atoms present in one unit of the following compounds is:

a). Potassium Iodide , KI = 2

b).Sodium Sulfide, $Na_{2}S$ = 3

c). Silicon Dioxide , $SiO_{2}$ = 3

d). Carbonic Acid ,$H_{2}CO_{3}$ = 6

Explanation:

Atomicity : It is defined as the number of atoms that are present in a given molecule/compound.

Atom : The smallest unit of matter is called atom. For e.g O is atom of oxygen but $O_{2}$ is not an atom , it is molecule of oxygen .

$O_{2}$ molecule has 2 atoms of Oxygen

Similarly  Na , K , Fe are atoms but $O_{2}$ ,$CO_{2}$ ,$N_{2}$,$H_{2}$  are molecules

a).Potassium Iodide

KI = 1 atom of K + 1 atom of I

Total atoms = 2

b) Sodium Sulfide

$Na_{2}S$ = 2 atoms of Na + 1 atom of S

Total atoms = 3

c) Silicon Dioxide

$SiO_{2}$ = 1 atom of Si + 2 atoms of O

Total atoms = 3

d) Carbonic Acid

$H_{2}CO_{3}$ = 2 atom of H + 1 atom of C + 3 atom of O

= 2+1+3

Total atoms = 6