Answer:
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Explanation:
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Answer: 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of
require = 1 mole of
Thus 0.061 moles of
will require=
of
Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 1 mole of
give = 1 mole of
Thus 0.061 moles of
give =
of
Mass of
Thus 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.
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Answer:
C. Tightly packed protons and neutrons
Explanation:
It consists of two sub-atomic particle namely proton and neutron.
This dense nucleus is responsible for most of the mass of atom.
0.4575 g of saccharine is present in the ten tablets of saccharine dissolved in water.
From the information in the question, the sulfur in saccharin (C7H5NO3S) was completely converted to sulfate ion (SO4^2-). This ion was now reacted with excess barium chloride to form barium sulfate BaSO4. This later reaction occurs as follows;
SO4^2-(aq) + Ba^2+(aq) --------> BaSO4(s)
Number of moles of BaSO4 obtained = 0.5240 g/233 g/mol
= 0.0025 moles
Since the reaction is 1:1, 0.0025 moles of sulfate ions from saccharine reacted.
Molar mass of saccharine = 7(12) + 5(1) + 14 + 3(16) + 32
= 84 + 5 + 14 + 48 + 32 = 183 g/mol
Mass of saccharine in the tablet = 0.0025 moles × 183 g/mol
= 0.4575 g
Learn more: brainly.com/question/1527403