The answer depends heavily on what 'objects' you're talking about.
-- <u><em>Current is measured in amps.</em></u> (You can use any symbol you want to represent current, but the most common one is " I ", not "Δ".)
-- <u><em>The relationship between current, voltage, and resistance is mathematically defined by Ohm's Law. </em></u>
-- <u><em>Current is the flow of electrons through a circuit.</em></u>
-- (Ohm's Law is NOT mathematically represented by the equation V=I/R.) <u><em>It should be V = I · R</em></u> .
(When solving for Resistance in a circuit and both voltage and current are known values, the equation I =V*R is not true, and not the way to solve it.) <u><em>If the resistance is what you're looking for, then the equation to use is </em></u><u><em>R = V / I</em></u><u><em> . </em></u>
<em>-- </em><u><em>If the voltage in a circuit is increased, the current will also increase.</em></u>
Answer:
=170kcal
Explanation:
We first calculate the amount of energy required to melt the alcohol using the formula: MLf, where Lf is the latent heat of fussion
We then calculate amount of heat required to raise the temperature of liquid alcohol to -14° C using MC∅. We then add the two.
Thus ΔH=MLf+MC∅
ΔH=2kg×25kcal/kg+ 2kg×(0.6kcal/kg.K×(-14-⁻114)
=50kcal+120kcal
=170kcal
Explanation:
the lights on Galaxy watch shifted of uniform amounts to what the rate in of the spectrum,regardless of the distance from Earth
Hey there!
In this case, it is possible to solve this problem by using the widely-known steam tables which show that at 90 °C, the pressure that produces a vapor-liquid mixture at equilibrium is about 70.183 kPa (Cengel, Thermodynamics 5th edition).
Moreover, for the calculation of the volume, it is necessary to calculate the volume of the vapor-liquid mixture, given the quality (x) it has:

Thus, since 8 kg correspond to liquid water, 2 kg must correspond to steam, so that the quality turns out:

Now, at this temperature and pressure, the volume of a saturated vapor is 2.3593 m³/kg whereas that of the saturated liquid is 0.001036 m³/kg and therefore, the volume of the mixture is:

This means that the volume of the container will be:

Regards!