<span>The unknown substance is silver.
I don't see a list of available substances, but let's see if there's something reasonable available that will match. First, let's calculate the density of the unknown substance. Density is mass per volume, so
273 g / 26 mL = 10.5 g/mL
Looking up a list of elements sorted by density, I see the following:
10.07 Actinium
10.22 Molybdenum
10.5 Silver
11.35 Lead
And silver at 10.5 g/ml is a very nice match for the unknown substances' density of 10.5 g/ml.</span>
Answer:
the pressure per square inch is greater from the smaller feet.
Explanation:
different weight distribution
Answer:
g'(10) = 
Explanation:
Since g is the inverse of f ,
We can write
g(f(x)) = x <em> </em><em>(Identity)</em>
Differentiating both sides of the equation we get,
g'(f(x)).f'(x) = 1
g'(10) = 
--equation[1] Where f(x) = 10
Now, we have to find x when f(x) = 10
Thus 10 = 
+ 2
= 8
x = 
Since f(x) = + 2
f'(x) = -
f'() = -4 × 4 = -16
Putting it in equation 1, we get:
We get g'(10) = -
Answer: The Porsche Wins. Arrives 19secs earlier before the Honda.
Explanation: The head start of 1secs corresponded with the difference in acceleration {3.5m/s² - 3m/s²}=0.5m/s²
Using the first equation of motion we obtain the velocity which correspond to this acceleration (0.5m/s²) and time of 1secs where initial velocity u = 0
V = u + at
V= 0 + at
V = 0.5 * 1 = 0.5m/s
Now let find the velocity of each of the car.
If V. a
0.5m/s 0.5m/s²
........m/s. 3.5m/s²
Velocity of porche Vp
= (3.5/0.5) * 0.5 = 3.5 m/s
Also if. V. a
0.5m/s. 0.5m/s²
.....m/s. 3 m/s²
Velocity of Honda Vh
= {3/0.5} * 0.5 = 3m/s
So let's find the time t taken by both cars to cover the distance of 400m
Recall,
Velocity = distance/time
Time t = distance/velocity
For Porche, t = 400/3.5 =114.29secs
For Honda, t = 400/3 = 133.33secs
Looking critically, we noticed that Porche car took shorter time.
The difference In time is
= (133.33 - 114.29)secs = 19.04secs
Well lets see, an ocean drying up is one, or another is that an earth quake flattened it. If this is an a b c or d question can I see the possible answers?
