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Novay_Z [31]
3 years ago
14

What type of reaction is shown below?

Chemistry
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:

Synthesis

Explanation:

Chemical equation:

3S + 2Fe → Fe₂S₃

The solid iron react with solid sulfur and form iron(III) sulfide. The reaction type is synthesis because,

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

A + B  → AB

Other options are incorrect because,

In double displacement  two compound exchange their ions and form new compounds.

AB + CD → AC +BD

In decomposition one reactant is break down into two or more product.

AB → A + B

In single replacement one elements replace the other element in compound.

AB + C → AC + B

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The arrangement of particles is least ordered in a sample of
lora16 [44]

Answer:

The arrangement of particles is least ordered is  a > c > b > d

Explanation:

Given that,

The arrangement of particles is least ordered in a sample of NaCl.

We know that,

The least ordered arrangement are.

The form of state of particle in least ordered.

So, The least ordered arrangement will be

aqua > gas > liquid > solid

The arrangement of particles is least ordered in a sample of NaCl

NaCl(aq) > NaCl(g) > NaCl(l) > NaCl(s)

Hence, The arrangement of particles is least ordered is a > c > b > d

4 0
3 years ago
What does it mean when a system or a reaction is endothermic?
ser-zykov [4K]
It means the system absorbs energy from surrounding objects; usually, but not always, involving heat
4 0
3 years ago
Read 2 more answers
Bromine (Br2) is produced by reacting HBr with O2, with water as a byproduct. The O2 is part of an air (21 mol % O2, 79 mol % N2
Karolina [17]

Answer:

The mole fractions:

x_{HBr}=\frac{100mol}{318.5}=0.314

x_{Br_2}=\frac{78mol}{318.5}=0.245

x_{H_2O}=\frac{78mol}{318.5}=0.245

x_{O_2}=\frac{62.5mol}{318.5}=0.196

Explanation:

The reaction described is:

2 HBr (g) + 1/2 O_2 (g) \longrightarrow Br_2 (g) + H_2O (g)

The limiting reactant is the HBr (oxygen is in excess).

a) The mass (in moles) balance for this sistem:

n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *n_{HBr}*0.78

(the 0.78 is because of the fractional conversion)

n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *n_{HBr}*1.25

(the 1.25 is because of the oxygen excess)

n_{H_2O}=\frac{ 1 mol H_2O}{1 mol Br_2} *n_{Br_2}

There is only one degree of freedom in this sistem, you can either deffine the moles of HBr you have or the moles of Br2 you want to produce. The other variables are all linked by the equations above.

b) Base of calculation 100 mol of HBr:

nn_{HBr}=100 mol HBr

n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *100mol HBr*0.78

n_{Br_2}=78 mol Br2

n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *100 mol HBr*1.25

n_{O_2}=62.5 mol O_2

n_{H_2O}=n_{Br_2}= 78 mol

n_{total}=(78+78+100+62.5)mol= 318.5mol

The mole fractions:

x_{HBr}=\frac{100mol}{318.5}=0.314

x_{Br_2}=\frac{78mol}{318.5}=0.245

x_{H_2O}=\frac{78mol}{318.5}=0.245

x_{O_2}=\frac{62.5mol}{318.5}=0.196

4 0
3 years ago
Use the equation to answer the question
vaieri [72.5K]

CH4 + 2O2→CO2 + 2H2O

Explanation:

CH4 + O2→CO2 + H2O

First look at the C atoms. At first glance they are balanced with 1 C on each side.

Now look at the H atoms. They are not balanced. There are 4 H atoms on the left side and 2 H atoms on the right. Place a coefficient of 2 in front of the H2O. We now have 4 H atoms on both sides.

CH4 + O2→CO2 + 2H2O

Now look at the O atoms. They are not balanced. There are 2 O atoms on the left side and 4 on the right. Place a coefficient of 2 in front of the O2. We now have 4 O atoms on both sides.

CH4 + 2O2→CO2 + 2H2O

The equation is now balanced. Each side has 1 C atom, 4 H atoms, and 4 O atoms.

6 0
3 years ago
Read 2 more answers
Nucleotides polymerize via condensation reactions. The reaction forms a new covalent bond—a phosphodiester linkage, or a phospho
Finger [1]

Answer:

The phosphodiester connects the 3′ carbon of one nucleotide to the 5′ carbon of another nucleotide

Explanation:

The phosphodiester bond is a covalent bond where a phosphate group is attached to adjacent C through an ester bond, which is a consequence of a condensation reaction between the two sugar hydroxyl groups and the phosphate group.

The diester bond between phosphoric acid and two sugar molecules in the DNA and RNA skeleton binds two nucleotides forming polymers known as oligonucleotides.

The phosphodiester bond binds a C3` with a C5` in both DNA and RNA

          (base)1-(sugar)-OH + HO-P(O)2-O-(sugar)-(base)2   ------>

------>   (base)1-(sugar)-O-P(O)2-O-(sugar)-(base)2  

During the reaction of two of the hydroxyl groups in phosphoric acid with a hydroxyl group in two other molecules two ester bonds in a phosphodiester group are formed. A condensation reaction in which a water molecule is lost generates each ester bond.

4 0
4 years ago
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