All categories

3 years ago

Write rhe equation of the line that passes through (3, 4) and (2, 1)

1 answer:

4 0

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{3}}}\implies \cfrac{-3}{-1}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{3}(x-\stackrel{x_1}{3}) \\\\\\ y-4=3x-9\implies y=3x-5$

You might be interested in

Which number can you add to get a sum of 0 A . -10 B. -5 C. 0 D. 5

Nikolay [14]

To figure this one out, my pre calculus teacher said to "plug and chug". Since you are adding each number to itself, A=-20, B=-10, C=0, and D=10. So your answer would be C.0

4 0

3 years ago

Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined$

7 0

3 years ago

Determine the horizontal, vertical, and slant asymptotes: y=x2+2x-3/x-7

densk [106]

Answer:

vertical asymptote: x = 7
slant asymptote: y = x+9

Step-by-step explanation:

The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.

There is no horizontal asymptote because the numerator is of higher degree than the denominator.

When you divide the numerator by the denominator, you get ...

y = (x +9) +60/(x -7)

Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.

3 0

3 years ago

-3w-3x-7w+4x-2w ......

valkas [14]

Answer:

− 1 2 +

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Simplify. Rewrite the expression in the form 4^n (4^6)(4^-8) =

stiks02 [169]

Answer:

4^-2

Step-by-step explanation:

The rules of exponents tell you ...

(a^b)(a^c) = a^(b+c)

This means ...

(4^6)(4^-8) = 4^(6-8) = 4^-2

7 0

3 years ago

Write rhe equation of the line that passes through (3, 4) and (2, 1)​

Write rhe equation of the line that passes through (3, 4) and (2, 1)