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notka56 [123]
3 years ago
6

Derive an approximate formula for the mutual inductance of two circular rings of the same radius a, arranged like wheels on the

same axle with their centers a distance b apart. Use an approximation good for b≫a.

Physics
1 answer:
son4ous [18]3 years ago
7 0

Answer:

Please check the attached file for the derivation

Explanation:

Check the attached file

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Now set the tension to low and wiggle the wrench to create more waves. Can you explain how moving the first point on the string,
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Answer:

When the string moves, it creates a very small change in the distance to the next point, th

Explanation:

When the string moves, it creates a very small change in the distance to the next point, this generates a restoring force that tends to push the string back, this small disturbance propagates along the string and is what creates the pulse.

This is similar to what happens when a spring is stretched and a restoring force is generated shaved by the law of shortening.

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A stone is launched from the ground, at a 70° angle, with an initial velocity of 120 m/s.
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<span>A) x = 41t
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A concave lens can only form a. A. real image. B. reversed image. C. virtual image. D. magnified image.
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Three charges are enclosed inside a spherical closed surface. The net flux through the surface is −216 N · m2/C. If two of the c
sladkih [1.3K]

Answer:

q₃ = -4.81 nC

Explanation:

We can use the Gauss Law here:

∅ = q/∈₀

where,

∅ = Net Flux = - 216 N.m²/C

q = total charge enclosed inside sphere = ?

∈₀ = permittivity of free space = 8.85 x 10⁻¹² C/N.m²

Therefore,

- 216 N.m²/C = q / 8.85 x 10⁻¹² C²/N.m²

q = (-216 N.m²/C)(8.85 x 10⁻¹² C²/N.m²)

q = - 1.91 nC

So, the total charge will be sum of all three charges:

q = q₁ + q₂ + q₃

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q₃ = - 1.91 nC - 1.74 nC - 1.16 nC

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