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inysia [295]
2 years ago
10

Suppose a solution was too concentrated for an accurate reading with the spectrophotometer. The concentrated solution was dilute

d by placing 1.00 mL of the concentrated solution in 4.00 mL of water. The solution was then placed in the spectrophotometer and an absorbance was obtained and after a few calculations the molar concentration was calculated to be 3.5 × 10–6 M. what was the concentraion of the original solution
Chemistry
1 answer:
yan [13]2 years ago
5 0
Using the law of <span>dilution:

</span>initial Molarity = 3.5x10⁻⁶ M

<span>Initial volume = 4.00 mL
</span>
final Molarity = ??

final volume = 1.00 mL

Therefore:

Mi x Vi = Mf x Vf

(3.5x10⁻⁶) x 4.00 = Mf x 1.00

1.4x10⁻⁵ = Mf x 1.00

Mf = 1.4x10⁻⁵ / 1.00 = 

 1.4x10⁻⁵ M 


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charle [14.2K]
Orbital
All atoms have the same number of electrons as protons. Negative electrons are attracted to the positive nucleus. This force of attraction keeps electrons constantly moving around the nucleus. The region where an electron is most likely to be found is called an orbital.
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Whats does the elements Li (lithium),B (boron, and Ne neon) have in common?
nikdorinn [45]
They are in the same period (horizontal)
8 0
3 years ago
If I have 21 liters of gas held at a pressure of 78 atm and a temperature of 900 K, what will
shusha [124]

Answer:

30.33L

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant  and Charles law states that the volume of a given mass of gas is directly proportional to the temperature provided the pressure remains constant

P1V1/T1 = P2V2/ T2

P1 =  78atm, V1 = 21L , T1 = 900K

P2 = 45atm, V2 = ? , T2 =750K

78× 21 / 900 = 45×V2 / 750

1638/900 = 45 V2 / 750

1638×750 = 900×45V2

1228500 = 40500V2

Divide both sides by 40500

1228500÷40500= V2

V2 = 30.33L

I hope this was helpful, please mark as brainliest

6 0
2 years ago
One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su
solong [7]

Answer:

89.55~\%~of~Fe_2O_3~in~the~sample

Explanation:

The first step in this reaction is the<u> converstion from Kg</u> of Fe <u>to</u>  <u>grams</u> of Fe_2O_3.

1.19x10^3~Kg~Fe~\frac{1000g~Fe}{1~Kg~Fe}~\frac{1~mol~Fe}{55.84~g~Fe}~\frac{1~mol~Fe_2O_3}{2~mol~Fe}~\frac{159.68~g~Fe_2O_3}{1~mol~Fe_2O_3}~\frac{1~Kg~Fe_2O_3}{1000~g~Fe_2O_3}

X~=~1.7x10^3~Kg~Fe_2O_3

Then we can calculate the <u>percentage</u> of  Fe_2O_3 in the sample:

\%~Fe_2O_3~=~\frac{1.7x10^3~Kg~Fe_2O_3}{1.9x10^3~Kg~Sample}*100

89.55~\%~of~Fe_2O_3~in~the~sample

3 0
3 years ago
What is the formula for Manganese (III) acetate?
AURORKA [14]

C6H9MnO6.2(H2O)

Here is the formula hope it helps.

3 0
3 years ago
Read 2 more answers
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