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inysia [295]
3 years ago
10

Suppose a solution was too concentrated for an accurate reading with the spectrophotometer. The concentrated solution was dilute

d by placing 1.00 mL of the concentrated solution in 4.00 mL of water. The solution was then placed in the spectrophotometer and an absorbance was obtained and after a few calculations the molar concentration was calculated to be 3.5 × 10–6 M. what was the concentraion of the original solution
Chemistry
1 answer:
yan [13]3 years ago
5 0
Using the law of <span>dilution:

</span>initial Molarity = 3.5x10⁻⁶ M

<span>Initial volume = 4.00 mL
</span>
final Molarity = ??

final volume = 1.00 mL

Therefore:

Mi x Vi = Mf x Vf

(3.5x10⁻⁶) x 4.00 = Mf x 1.00

1.4x10⁻⁵ = Mf x 1.00

Mf = 1.4x10⁻⁵ / 1.00 = 

 1.4x10⁻⁵ M 


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