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Llana [10]
3 years ago
13

If an atom of hydrogen loses its electron, what is its charge?

Chemistry
2 answers:
Alex17521 [72]3 years ago
6 0

Since it is specifically stated that the hydrogen is an atom and not an ion, therefore it is written simple as H (not H+). So since an atom of Hydrogen (H) has one proton and one electron and it loses its electron, therefore it is left with one proton, therefore now it becomes an ion of H+.

So answer is its charge is +1.

 

Answer:

<span>D. +1</span>

Stells [14]3 years ago
4 0

answer      +1

explanation

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B. The following reaction takes place in a basic solution. (7 points)
Natali5045456 [20]

<u>Answer:</u> The final equation has hydroxide ions which indicate that the reaction has occurred in a basic medium.

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously.

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

The given redox reaction follows:

MnO_4^-(aq)+NO_2^-(aq)\rightarrow MnO_2(s)+NO_3^-(aq)

To balance the given redox reaction in basic medium, there are few steps to be followed:

  • Writing the given oxidation and reduction half-reactions for the given equation with the correct number of electrons

Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-

  • Multiply each half-reaction by the correct number in order to balance charges for the two half-reactions

Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-         ( × 3)

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-             ( × 2)

The half-reactions now become:

Oxidation half-reaction: 3NO_2^-+6OH^-\rightarrow 3NO_3^-+3H_2O+6e^-

Reduction half-reaction: 2MnO_4^-+4H_2O+3e^-\rightarrow 2MnO_2+8OH^-

  • Add the equations and simplify to get a balanced equation

Overall redox reaction: 3NO_2^-+2MnO_4^-+H_2O\rightarrow 3NO_3^-+2MnO_2+2OH^-

As we can see that in the overall redox reaction, hydroxide ions are released in the solution. Thus, making it a basic solution

3 0
3 years ago
What is formed when water chemically combines with carbon dioxide
solong [7]

When water chemically combines with carbon dioxide, a Carbonic acid is formed.

<u>Explanation</u>:

  • Carbon dioxide responds with water in a solution to form a weak acid, carbonic acid. Carbonic acid disassociates into hydrogen particles and bicarbonate particles. The hydrogen particles and water respond with the most basic minerals modifying the minerals.  
  • Carbon dioxide and the other atmospheric gases disintegrate in surface waters. Dissolved gases are in equilibrium with the gas in the atmosphere. Carbon dioxide responds with water in a solution to form the weak acid, carbonic acid. Carbonic acid disassociates into hydrogen particles and bicarbonate particles.  
  • The hydrogen particles and water respond with the most basic minerals altering the minerals. The results of enduring are prevalently clays and soluble particles, for example, calcium, iron, sodium, and potassium. Bicarbonate particles additionally remain in solution; a remnant of the carbonic acid that was utilized to weather the rocks.

5 0
3 years ago
Sulfur dioxide has a vapor pressure of 462.7 mm Hg at –21.0 °C and a vapor pressure of 140.5 mm Hg at –44.0 °C. What is the enth
stealth61 [152]

Answer : The value of \Delta H_{vap} is 28.97 kJ/mol

Explanation :

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature -21.0^oC = 462.7 mmHg

P_2 = vapor pressure at temperature -44.0^oC = 140.5 mmHg

\Delta H_{vap} = Enthalpy of vaporization = ?

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = -21.0^oC=[-21.0+273]K=252K

T_2 = final temperature = 45^oC=[-41.0+273]K=232K

Putting values in above equation, we get:

\ln(\frac{140.5mmHg}{462.7mmHg})=\frac{\Delta H_{vap}}{8.314J/mol.K}[\frac{1}{252}-\frac{1}{232}]\\\\\Delta H_{vap}=28966.6J/mol=28.97kJ/mol

Therefore, the value of \Delta H_{vap} is 28.97 kJ/mol

4 0
4 years ago
(3 Points)
prisoha [69]
Your answer is B. radio waves have shorter wavelenghts than microwaves.
Have a great day
5 0
4 years ago
Read 2 more answers
1. Write the balanced chemical equation for the synthesis of magnesium phosphide from its elements, including the word “energy”
Evgen [1.6K]

Answer:

3Mg(s) +2P(s) -------> Mg3P2(s) + energy

Keq= [Mg3P2]/[Mg]^3 [P]^2

Explanation:

The equation for the formation of magnesium phosphide from its elements is;

3Mg(s) +2P(s) -------> Mg3P2(s) + energy

Hence we can see that three moles of magnesium atoms combines with two moles of phosphorus atoms to yield one mole of magnesium phosphide. The equation written above is the balanced chemical reaction equation for the formation of the magnesium phosphide.

The equilibrium expression for the reaction K(eq) will be given by;

Keq= [Mg3P2]/[Mg]^3 [P]^2

8 0
4 years ago
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