Answer:
radius = 9.1 × 
m
Explanation:
given data
applied load = 5560 N
flexural strength = 105 MPa
separation between the support = 45 mm
solution
we apply here minimum radius formula that is
radius = ![\sqrt[3]{\frac{FL}{\sigma \pi}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7BFL%7D%7B%5Csigma%20%5Cpi%7D%7D)
.................1
here F is applied load and is length
put here value and we get
radius = ![\sqrt[3]{\frac{5560\times 45\times 10^{-3}}{105 \times 10^6 \pi}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B5560%5Ctimes%2045%5Ctimes%2010%5E%7B-3%7D%7D%7B105%20%5Ctimes%2010%5E6%20%5Cpi%7D%7D)
solve it we get
radius = 9.1 × m
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Answer:
The answer is False.
Explanation:
When it comes to occupational safety,<em> it is very important for ladders to be inspected by a qualified person before each use.</em> This is because ladders undergo conditions that impact their integrity while being in use. The inspection is also essential in order for the ladder to be timely replaced.
<u><em>Ladder accidents or ladder-related injuries happen every year.</em></u> Around 700 occupational deaths due to elevated fall from a ladder accounts for 15% of all occupational deaths. Misuse or damage ladders are often the reasons for this.
Thus, the answer in the above statement is False because ladders are required to be inspected for visible defects prior to the first use of each work shift and after any occurrence that could affect their safety.
