Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
Answer:
you fill the hole so there is no more cat
Answer:
option c is correct
47.2%
Explanation:
given data
consisting of refrigerant = 134 a
volume V = 0.01 m³/kg
pressure P = 1MPa = 1000 kPa
to find out
quality of the R 134a
solution
we will get here value of volume Vf and Vv from pressure table 60 kpa to 3 Mpa for 1 Mpa of R134 a
that is
Vf = 0.0008701 m³/kg
Vv = 0.0203 m³/kg
so we will apply here formula that is
quality = (V - Vf) / (Vv - Vf) ............1
put here value
quality = (0.01 - 0.0008701 ) / ( 0.0203 - 0.0008701 )
quality = 0.4698
so quality is 47 %
SO OPTION C IS CORRECT
Answer:
293 kg
Explanation:
Let's say the tension in each cable is Tb, Tc, and Td.
First, find the length of cable AD:
r = √(2² + 2² + 1²)
r = 3
Using similar triangles:
Tdx = 2/3 Td
Tdy = 2/3 Td
Tdz = 1/3 Td
Sum of the forces in the x direction:
∑F = ma
Tb − 2/3 Td = 0
Td = 3/2 Tb
Sum of the forces in the y direction:
∑F = ma
2/3 Td − Tc = 0
Td = 3/2 Tc
Sum of the forces in the z direction:
∑F = ma
1/3 Td − mg = 0
Td = 3mg
From the first two equations, we know Td is greater than Tb or Tc. So we need to set Td to 8.6 kN, or 8600 N.
8600 N = 3mg
m = 8600 N / (3 × 9.8 m/s²)
m ≈ 292.5 kg
Rounded to three significant figures, the maximum mass of the crate is 293 kg.
Answer:
The value of R is 10101
Explanation:
As per the given data
D = 1000100100
G = 100101
Redundant bit = 6-bits - 1-bit = 5-bits
No add fice zero to D
D = 100010010000000
Now calculate R as follow
R = D / G
R = 100010010000000 / 100101
R = 10101
Workings are attached with this question
