Answer: The mass of air present in the room is 37.068 kg
Explanation : Given,
Length of the room = 10.0 ft
Breadth of the room = 11.0 ft
Height of the room = 10.0 ft
To calculate the volume of the room by using the formula of volume of cuboid, we use the equation:
where,
V = volume of the room
l = length of the room
b = breadth of the room
h = height of of the room
Putting values in above equation, we get:
Conversion used : 
Now we have to calculate the mass of air in the room.
Conversion used : (1 kg = 1000 g)
Therefore, the mass of air present in the room is 37.068 kg
Answer:
False
Explanation:
A significant number is a number that is used to express the accuracy in a measurement. There are some rules that binds the identification of significant figures when reporting a scientific measurement.
- All non-zero numbers are significant
- Zeros in between two digits are significant.
- Zeros to the right of the decimal are significant.
- Leading zeros are just place holders and are not significant.
- Trailing zero in a whole number with decimal is significant
- Trailing zero without a decimal is not significant.
source: http://ccnmtl.columbia.edu/projects/mmt/frontiers/web/chapter_5/6665.html
We can see that not all zeros in a measurement is significant. For example, 540 has 2 significant numbers because the zero is not significant but 540.2 has 4 significant numbers.
Answer:
c
Explanation:
A pathogen or infectious agent is a biological agent that causes disease or illness to its host. The term is most often used for agents that disrupt the normal physiology of a multicellular animal or plant. However, pathogens can infect unicellular organisms from all of the biological kingdoms.
Answer:
6.02 x 1023 number of atoms in one mole.
Explanation:
i cant show work because i dont want to be loud in 3 in the moring
Answer:
k' = (2.0345 × 10⁻⁸) M/s.
Explanation:
Beer-Lambert's law explains that Absorbance is directly proportional to the concentration of the substrate under consideration.
A ∝c
A = εlc
where ε = molar absorptivity constant = 87,000 M⁻¹cm⁻¹
l = path length of the solution that the light passes through in cm = 1 cm for most cases.
c = concentration of the substrate.
In terms of rate terms,
A' = εlc'
where A' has units of Absorbance/s
c' = rate of reaction, units of concentration/s
A' = εlc'
From the graph, the slope of the graph = 0.00177 Absorbance/s
0.00177 = 87000 × 1 × c'
c' = (0.00177/87000)
c' = (2.0345 × 10⁻⁸) M/s.
This value is the pseudo rate constant, k'.
Hope this Helps!!!
