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malfutka [58]
3 years ago
5

The energy required to split apart dichlorine according to the equation is 3.99 × 10-19 J/molecule. Cl2(g) → 2Cl(g) Calculate th

e frequency (Hz) of the photon that can dissociate dichlorine. Express answer in scientific notation.
Chemistry
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

The frequency of the photon that can dissociate dichlorine is 6.02×10¹⁴ Hz

Explanation:

The energy of a photon is given by the equation:

E=h·f

E=3.99×10⁻¹⁹ J/molecule

h (Planck's constant)=6.626×10⁻³⁴ m²·kg/s

∴ f=E/h

f=\frac{3.99*10^{-19}J}{6.626*10^{-34} m²·kg/s}=6.02×10¹⁴ s⁻¹= 6.02×10¹⁴ Hz

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Be sure to answer all parts. In the average adult male, the residual volume (RV) of the lungs, the volume of air remaining after
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<u>Answer:</u>

<u>For a:</u> The number of moles of air present in the RV is 0.047 moles

<u>For b:</u> The number of molecules of gas is 2.83\times 10^{22}

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

PV=nRT

where,

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n = number of moles of air = ?

Putting values in above equation, we get:

1.00atm\times 1.2L=n_{air}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 310K\\n_{air}=\frac{1.00\times 1.2}{0.0821\times 310}=0.047mol

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  • <u>For b:</u>

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1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.047 moles of air will contain (0.047\times 6.022\times 10^{23})=2.83\times 10^{22} number of gas molecules.

Hence, the number of molecules of gas is 2.83\times 10^{22}

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