The energy required to split apart dichlorine according to the equation is 3.99 × 10-19 J/molecule. Cl2(g) → 2Cl(g) Calculate th
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<u>Answer:</u>
<u>For a:</u> The number of moles of air present in the RV is 0.047 moles
<u>For b:</u> The number of molecules of gas is
<u>Explanation:</u>
- <u>For a:</u>
To calculate the number of moles, we use the equation given by ideal gas follows:
where,
P = pressure of the air = 1.00 atm
V = Volume of the air = 1200 mL = 1.2 L (Conversion factor: 1 L = 1000 mL)
T = Temperature of the air =
R = Gas constant =
n = number of moles of air = ?
Putting values in above equation, we get:
Hence, the number of moles of air present in the RV is 0.047 moles
- <u>For b:</u>
According to mole concept:
1 mole of a compound contains number of molecules.
So, 0.047 moles of air will contain number of gas molecules.
Hence, the number of molecules of gas is