Where is air pressure greater exophere or trophere
1 answer:
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Answer:
Explanation:
<u><em>1. First determine the empirical formula.</em></u>
a) Base: 100 g of compound
mass atomic mass number of moles
g g/mol mol
C 26.06 12.011 26.06/12.011 = 2.17
H 13.13 1.008 13.13/1.008 = 13.03
N 60.81 14.007 60.81/14.007 = 4.34
b) Divide every number of moles by the smallest number: 2.17
mass number of moles proportion
C 2.17/2.17 1
H 13.03/2.17 6
N 4.34/2.17 2
c) Empirical formula
d) Mass of the empirical formula
<u><em>2. Molecular formula</em></u>
Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula: