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STatiana [176]
2 years ago
6

A mechanical wave is created when a source of energy causes _____.

Physics
1 answer:
earnstyle [38]2 years ago
3 0

\huge \tt \: { \blue{ \fbox{ \purple{\underbrace{ \pink{\overbrace{\green{Answer}}}}}}}}

A mechanical wave is created when a source of energy causes \sf \bf   {\underline{a  \:  \: vibration  \:  \: to \:  \:  travel \:  \:  through  \:  \: a  \:  \: medium }}

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Calculate the RMS voltage of the following waveforms with 10 V peak-to-peak:
Deffense [45]

Answer:

a) T=0.01s

b) T=0.001s

c) T=0.00001s

Explanation:

From the question we are told that:

Given Frequencies

a. 100 Hz,

b. 1 kHz,

c. 100 kHz.

Generally the equation for Waveform Period is mathematically given by

T=\frac{1}{f}

Therefore

a)

For

T=100 Hz

T=\frac{1}{100}

T=0.01s

b)

For

F=1kHz

T=\frac{1}{1000}

T=0.001s

c)

For

F=100kHz

T=\frac{1}{100*100}

T=0.00001s

6 0
3 years ago
When light passes through a convex lens, it does this.....
Tpy6a [65]

Explanation:

6. Converge or come together

7. convex

3 0
3 years ago
Read 2 more answers
What is the frequency of an x- ray if the wavelength is 4.5 E - 10m?
AnnZ [28]
V (speed) = F (frequency) x Wavelength
If we rearrange the formula, making frequency the subject;
F (frequency) = Speed ÷ Wavelength
F = 300,000 m\s x 4.5 e -10m
F = 0.08810409956 Hz
4 0
3 years ago
A block whose weight is 45.8 N rests on a horizontal table. A horizontal force of 36.6 N is applied to the block. The coefficien
Liula [17]

Answer:

Yes it will move and a= 4.19m/s^2

Explanation:

In order for the box to move it needs to overcome the maximum static friction force

Max Static Friction = μFn(normal force)

plug in givens

Max Static friction = 31.9226

Since 36.6>31.9226, the box will move

Mass= Wieght/g which is 45.8/9.8= 4.67kg

Fnet = Fapp-Fk

= 36.6-16.9918

=19.6082

=ma

Solve for a=4.19m/s^2

7 0
3 years ago
Which of the following wavelengths will produce standing waves on a string that is 3.5 m long?
denpristay [2]

In a string of length L, the wavelength of the n-th harmonic of the standing wave produced in the string is given by:

\lambda=\frac{2}{n} L


The length of the string in this problem is L=3.5 m, therefore the wavelength of the 1st harmonic of the standing wave is:

\lambda=\frac{2}{1} \cdot 3.5 m=7.0 m


The wavelength of the 2nd harmonic is:

\lambda=\frac{2}{2} \cdot 3.5 m=3.5 m


The wavelength of the 4th harmonic is:

\lambda=\frac{2}{4} \cdot 3.5 m=1.75 m


It is not possible to find any integer n such that \lambda=5 m, therefore the correct options are A, B and D.

3 0
3 years ago
Read 2 more answers
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