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2 years ago

A mechanical wave is created when a source of energy causes _____.

Physics

1 answer:

earnstyle [38]2 years ago

3 0

$\huge \tt \: { \blue{ \fbox{ \purple{\underbrace{ \pink{\overbrace{\green{Answer}}}}}}}}$

A mechanical wave is created when a source of energy causes $\sf \bf {\underline{a \: \: vibration \: \: to \: \: travel \: \: through \: \: a \: \: medium }}$

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A dolphin in an aquatic show jumps straight up out of the water at a velocity of 11.8 m/s. The magnitude of the gravitational ac

siniylev [52]

Answer:

a) $y_{max}=7.10m$

b) $t=2.40 s$

Explanation:

From the exercise, we know the initial velocity, gravitational acceleration and initial position of the dolphin.

$v_{oy}=11.8m/s$

$y_{o}=0m\\ g=9.8m/s^{2}$

a) To find maximum height, we know that at that point the dolphin's velocity is 0 and it becomes coming down later.

Knowing that, we need to know how much time does it take the dolphin to reach maximum height.

$v_{y}=v_{oy}+gt$

$0=11.8m/s-(9.8m/s^{2} )t$

Solving for t

$t=1.20 s$

So, the dolphin reach maximum point at 1.20 seconds

Now, using the equation of position we can calculate maximum height.

$y=y_{o}+v_{oy}t +\frac{1}{2}gt^{2}$

$y=0+11.8m/s(1.20s)-\frac{1}{2}(9.8m/s^{2} )(1.20s)=7.10m$

b) To find how long is the dolphin in the air we need to analyze it's hole motion

At the end of the jump the dolphin return to the water at y=0. So, from the equation of position we have that

$y=y_{o}+v_{oy}t +\frac{1}{2}gt^{2}$

$0=0+11.8t-\frac{1}{2}(9.8)t^{2}$

What we have here, is a quadratic equation that could be solve using:

$t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

$a=-\frac{1}{2} (9.8)$

$b=11.8\\c=0$

$t=0s$ or $t=2.40 s$

Since the answer can not be 0, the dolphin is 2.40 seconds in the air.

4 0

3 years ago

A student constructed a series circuit consisting of a 12.0-volt battery, a 10.0-ohm lamp, and a

vesna_86 [32]

I thought you were going to ask for the resistance of the unknown
series resistor. Since you only want the equivalent resistance of the
circuit, you don't even need to know the resistance of the lamp.

I = E / R

Current through the circuit = (voltage of the battery) / (circuit resistance).

0.5 = (12) / R

Multiply each side by 'R' : (0.5) R = 12

Multiply each side by 2 : R = 24 ohms

(Since the resistance of the lamp is 10 ohms, the
unknown series resistor is the other 14 ohms.)

7 0

4 years ago

A 3-kg rock falls for 5 sec. What is its speed after falling for 5 sec? Reminder - Acceleration due to gravity, on Earth = 9.8 m

GaryK [48]

Here too when an object is dropped, we know the initial velocity is zero when in free fall. So V =g*t this implies V= 9.8 *5=49m/s..... do you get it?

3 0

3 years ago

The weight of a body above sea level varies inversely with the square of the distance from the center of Earth. If a woman weigh

Serjik [45]

Answer:

89.16pounds

Explanation:

The equation that defines this problem is as follows

W=k/X^2

where

W=Weight

K= proportionality constant

X=distance from the center of Earth

first we must find the constant of proportionality, with the first part of the problem

k=WX^2=131x3960^2=2054289600pounds x miles^2

then we use the equation to calculate the woman's weight with the new distance

W=2054289600/(4800)^2=89.16pounds

4 0

3 years ago

A research-level Van de Graaff generator has a 2.15 m diameter metal sphere with a charge of 5.05 mC on it. What is the potentia

Llana [10]

Answer:

42.3 MV

Explanation:

d = diameter of the metal sphere = 2.15 m

r = radius of the metal sphere

diameter of the metal sphere is given as

d = 2r

2.15 = 2 r

r = 1.075 m

Q = charge on sphere = 5.05 mC = 5.05 x 10⁻³ C

Potential near the surface is given as

$V = \frac{kQ}{r}$

$V = \frac{(9\times 10^{9})(5.05\times 10^{-3})}{1.075}$

V = 4.23 x 10⁷ volts

V = 42.3 MV

5 0

4 years ago