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Evgesh-ka [11]
2 years ago
7

A 12 V battery is connected across a device with variable resistance. As the resistance of the device increases, determine wheth

er the following quantities increase, decrease, or remain unchanged. HINT (a) The current through the device. increases decreases remains unchanged (b) The voltage across the device. increases decreases remains unchanged (c) The power consumed by the device. increases decreases remains unchanged
Physics
1 answer:
Arlecino [84]2 years ago
8 0

Answer:

a) DECREASE, b) INCREASE, c)  power remains constant

Explanation:

The resistance and the battery are connected in series.

a) How the current changes when the resistance changes

               V = I R

               I = V / R

               I = 12 / R

if the resinification increases, the current must DECREASE

b) when you check the expression

                V= I R

, if R increases the voltage of the INCREASE

c) the power in an electric circuit is

               P = I V

               

Let's analyze this expression, the voltage increases linearly with the increase in resistance and the current decreases linearly with the increase in r, for which the two effects are compensated and the dissipated power remains constant

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What is a travelling wave and a standing wave? What are the differences between both of them?

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I hope it helps, Regards.
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What is the distance from one crest to the next crest?
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2 years ago
Andrea's near point is 20.0 cm and her far point is 2.0 m. Her contact lenses are designed so that she can see objects that are
Shalnov [3]

Answer:

the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

Explanation:

Given the data in the question,

near point = 20 cm

far point = 2 m = 200 cm

Now, for an object that is infinitely far away, the image is at is its far point.

so using the following expression, we can determine the focal length

1/f = 1/i + 1/o

where f is the focal length, i is the image distance and o is the object distance.

here, far point i = 2 m = 200 cm  and v is ∞

so we substitute

1/f = 1/(-200 cm)  +  1/∞

f = -200 cm

Also, for object at its closest point, the image appear at near point,

so

1/f = 1/i + 1/o

we make o the subject of formula

o = ( i × f ) / ( i - f )

given that near point i = 20 cm

we substitute

o = ( -20 × -200 ) / ( -20 - (-200) )

o = 4000 / 180

o = 22.2 cm

Therefore, the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

4 0
3 years ago
Two coils have the same number of circular turns and carry the same current. Each rotates in a magnetic field acting perpendicul
Delicious77 [7]

Answer:

The radius of coil 2 = 2.7 cm

Explanation:

The number of coils = 2

It is given that both carry equal current and rotates in the magnetic field.

The given radius of coil 1 = 4.0 cm

Coil 1 rotates = 0.21 T field

Coil 2 rotates = 0.45 T filed.

The radius of coil 2 need to be calculated.

Torque action on dipole is given byT =NIABsinθ

here T1 = T2

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Both are doing because they have chorus
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