Explanation:
The newton (symbol: N) is the International System of Units (SI) derived unit of force.
Answer:
Incomplete question
This is the complete question
For a magnetic field strength of 2 T, estimate the magnitude of the maximum force on a 1-mm-long segment of a single cylindrical nerve that has a diameter of 1.5 mm. Assume that the entire nerve carries a current due to an applied voltage of 100 mV (that of a typical action potential). The resistivity of the nerve is 0.6ohms meter
Explanation:
Given the magnetic field
B=2T
Lenght of rod is 1mm
L=1/1000=0.001m
Diameter of rod=1.5mm
d=1.5/1000=0.0015m
Radius is given as
r=d/2=0.0015/2
r=0.00075m
Area of the circle is πr²
A=π×0.00075²
A=1.77×10^-6m²
Given that the voltage applied is 100mV
V=0.1V
Given that resistive is 0.6 Ωm
We can calculate the resistance of the cylinder by using
R= ρl/A
R=0.6×0.001/1.77×10^-6
R=339.4Ω
Then the current can be calculated, using ohms law
V=iR
i=V/R
i=0.1/339.4
i=2.95×10^-4 A
i=29.5 mA
The force in a magnetic field of a wire is given as
B=μoI/2πR
Where
μo is a constant and its value is
μo=4π×10^-7 Tm/A
Then,
B=4π×10^-7×2.95×10^-4/(2π×0.00075)
B=8.43×10^-8 T
Then, the force is given as
F=iLB
Since B=2T
F=iL(2B)
F=2.95×10^-4×2×8.34×10^-8
F=4.97×10^-11N
Answer:
C. Energy is used for life processes (e.g. Movement, breathing, etc.)
Explanation:
As we pass from one trophic level to the next, only 10% of energy is transferred from the first trophic level to the next. This is because a lot of energy is lost to the surroundings and rest is utilised by the organism.
Nickel has a happy amount of 28 electrons.
Answer:
10.15Ω
Explanation:
From ohm's law,
V = IR...................... Equation 1
Where V = Voltage, I = current, R = resistance.
Assume the voltage across the resistance = V,
Given: I = 6.3 A
Substitute into equation 1
V = 6.3R.................. Equation 2
When an additional resistance of 3.4 Ω is inserted in series with R,
The voltage remain the same, but the current changes
Total Resistance(Rt) = (R+3.4)Ω, I' = 4.72 A
Also from ohm' law,
V = I'Rt............... Equation 3
Substitute the value of I' and Rt into equation 3
V = 4.72(R+3.4)............... Equation 5.
Divide equation 2 by equation 5
V/V = 6.3R/4.72(R+3.4)
1 = 1.335R/(R+3.4)
1 = 1.335R/(R+3.4)
R+3.4 = 1.335R
3.4 = 1.335R-R
3.4 = 0.335R
R = 3.4/0.335
R = 10.15Ω
