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Alborosie
3 years ago
11

Maria and Ben are both suffering from a hereditary disease, as described in the following table.

Physics
2 answers:
Firlakuza [10]3 years ago
7 0

Your answer would be B hope this helps!

Margaret [11]3 years ago
3 0
The answer is option B
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PLEASE HELPPP! :))))
serious [3.7K]

Answer:

Jupiter Neptune moon Uranus

Explanation:

3 0
2 years ago
A car goes around a curve of radius r at a constant speed v. Then it goes around a curve ofradius 2r at speed 2v. What is the ce
Rainbow [258]

The centripetal force on the car as it goes around the second curve is twice that compared to the first.

What is Centripetal force?

It is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation.

The formula of Centripetal force is:

F(c) = (m* v^2) / r

Here,

At the first curve,

The curve of radius = r

The constant speed = v

At the second curve,

The car speed (v')= 2 v

The radius of the curve (r')=2 r

According to the formula of centripetal Force:

As the car goes around the second curve,

F'(c) = m*v'^2 / r'

F'(c) = m* (2*v)^2 / 2r

F'(c) = 2* F

Thus,

The centripetal force on the car as it goes around the second curve is twice that compared to the first.

Learn more about centripetal force here:

<u>brainly.com/question/14317060</u>

#SPJ4

8 0
1 year ago
A body has masses of 0.013kg and 0.012kg in oil and water respectively, if the relative density of oil is 0.875, calculate the m
konstantin123 [22]

Answer:

the mass of the body is 0.02 kg.

Explanation:

Given;

relative density of the oil, \gamma _0 = 0.875

mass of the object in oil, M_o = 0.013 kg

mass of the object in water, M_w = 0.012 kg

let the mass of the object in air = M_a

weight of the oil, W_0 = M_a - 0.013

weight of the water, W_w = M_a - 0.012

The relative density of the oil is given as;

\gamma_0 = \frac{density \ of \ oil }{density \ of \ water} = \frac{W_0}{W_w} = \frac{M_a -0.013}{M_a -0.012} \\\\0.875 = \frac{M_a -0.013}{M_a -0.012}\\\\0.875(M_a - 0.012) = M_a - 0.013\\\\0.875M_a - 0.0105 = M_a -0.013\\\\0.875M_a - M_a = 0.0105 - 0.013\\\\-0.125 M_a = -0.0025\\\\M_a = \frac{0.0025}{0.125} \\\\M_a = 0.02 \ kg

Therefore, the mass of the body is 0.02 kg.

6 0
2 years ago
What is the resistance of the coil A at 600 kelvin if its resistance at 300 kelvin is 50 ohms? (Assume the temperature coefficie
leonid [27]

155Ω

Explanation:

R = R ref ( 1 + ∝ ( T - Tref)  

where R = conduction resistance at temperature T

R ref = conductor resistance at reference temperature

∝ = temperature coefficient of resistance for conductor

T = conduction temperature in degrees Celsius

T ref = reference temperature that ∝ is specified at for the conductor material

T = 600 k - 273 k = 327 °C

Tref = 300 - 273 K = 27 °C

R = 50 Ω ( 1 + 0.007 ( 327 - 27) )

R = 155Ω

8 0
3 years ago
Read 2 more answers
The four tires of an automobile are inflated to a gauge pressure of 2.2 105 Pa. Each tire has an area of 0.023 m2 in contact wit
Stels [109]

Answer:

Force, F = 20240 N

Explanation:

It is given that,

Pressure exerted by the four tires of an automobile, P=2.2\times 10^5\ Pa

Area of each tire, A=0.023\ m^2

Area of 4 tires,  A=0.092\ m^2

We know that the pressure exerted by an object is equal to the force per unit area. Its formula is given by :

P=\dfrac{F}{A}

F=P\times A

F=2.2\times 10^5\times 0.092

F = 20240 N

So, the weight of the automobile is 20240 N. Hence, this is the required solution.

7 0
3 years ago
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