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-Dominant- [34]
3 years ago
13

8.

Physics
1 answer:
GuDViN [60]3 years ago
5 0

This ratio (Fnet/m) is sometimes called the gravitational field strength

and is expressed as 9.8 N/kg ⇒ answer D

Explanation:

The gravitational field strength at a point is:

  • The gravitational force exerted per unit mass placed at that point.
  • This means that the gravitational field strength, g is equal to the force experienced by a mass of 1 kg in that gravitational field
  • Gravitational field strength = Weight/mass
  • Its unit is Newton per kilogram
  • Gravitational field strength ≈ 9.8 N/kg

From the notes above

The ratio \frac{F_{net}}{mass} = Gravitational field strength (g)

The answer is:

This ratio (Fnet/m) is sometimes called the gravitational field

strength and is expressed as 9.8 N/kg

Learn more:

You can learn more about gravitational field strength in brainly.com/question/6763771

LearnwithBrainly

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The total resistance of a parallel circuit is 25 ohms. If the total current is 100mA, how much current is through a 220 ohm resi
gulaghasi [49]

Answer:

The current across the resistance is 0.011 A.

Explanation:

Total resistance, R = 25 ohms

Total current, I = 100 mA = 0.1 A

Let the voltage is V.

By the Ohm's law

V = I R

V = 0.1 x 25 = 2.5 V

Now the resistance is R' = 220 ohm

As they are in parallel so the voltage is same. Let the current is I'.

V = I' x R'

2.5 = I' x 220

I' = 0.011 A

7 0
2 years ago
Metals in group 1 on the periodic table most commonly form which type of ion
givi [52]

Answer:

Group 1 - the alkali metals. The Group 1 elements in the periodic table are known as the alkali metals.

Explanation:

7 0
3 years ago
Two cars, initially at rest and 5 km apart at t=0 , simultaneously move toward each other. Car A travels at a constant speed of
Anastasy [175]

Answer:

<em>d. 268 s</em>

Explanation:

<u>Constant Speed Motion</u>

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

Where  

v = Speed of the object

d = Distance traveled

t  = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

\displaystyle t=\frac{d}{v}

Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.

The time it will take for them to meet is:

\displaystyle t=\frac{5}{67}

t = 0.0746 hours

Converting to seconds: 0.0746*3600 = 268.56

The closest answer is d. 268 s

8 0
3 years ago
A block of mass m is attached to a rope wound around the outer rim of a disk of radius R and moment of inertia I, which is free
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Answer:

Explanation:

I is the moment of inertia of the pulley, α is the angular acceleration of the pulley and T is the tension in the rope. Let a is the linear acceleration.

The relation between the linear acceleration and the angular acceleration is

a = R α   .... (1)

According to the diagram,

T x R = I x α

T x R = I x a / R      from equation (1)

T = I x a / R²      .... (2)

mg - T = ma    .... (3)

Substitute the value of T from equation (2) in equation (3)

mg - \frac{Ia}{R^{2}}=ma

a=\frac{mg}{m+\frac{I}{R^{2}}}

T is the acceleration in the system

Substitute the value of a in equation (2)

T = \frac{I}{R^{2}}\times \frac{mg}{m+\frac{I}{R^{2}}}

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This is the tension in the string.

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3 years ago
..................,,,,,,,,,
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Answer:

.....,.,.,.,.,.,.,.,.,.,.,.,..,.,.,.,.,.,.,,.,.┌(・。・)┘♪

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