8.
1 answer:
This ratio (Fnet/m) is sometimes called the gravitational field strength
and is expressed as 9.8 N/kg ⇒ answer D
Explanation:
The gravitational field strength at a point is:
- The gravitational force exerted per unit mass placed at that point.
- This means that the gravitational field strength, g is equal to the force experienced by a mass of 1 kg in that gravitational field
- Gravitational field strength = Weight/mass
- Its unit is Newton per kilogram
- Gravitational field strength ≈ 9.8 N/kg
From the notes above
The ratio = Gravitational field strength (g)
The answer is:
This ratio (Fnet/m) is sometimes called the gravitational field
strength and is expressed as 9.8 N/kg
Learn more:
You can learn more about gravitational field strength in brainly.com/question/6763771
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Answer:
A) K / K₀ = 4 b) v / v₀ = 4
Explanation:
A) For this exercise we can use the conservation of mechanical energy
in the problem it indicates that the displacement was doubled (x = 2xo)
starting point. At the position of maximum displacement
Em₀ = Ke = ½ k (2x₀)²
final point. In the equilibrium position
= K = ½ m v²
Em₀ = Em_{f}
½ k 4 x₀² = K
(½ K x₀²) = K₀
K = 4 K₀
K / K₀ = 4
B) the speed value
½ k 4 x₀² = ½ m v²
v = 4 (k / m) x₀
if we call
v₀ = k / m x₀
v = 4 v₀
v / v₀ = 4