The percentage of sugar in the solution is 1%
To solve this question, we need to find the percentage of 6 out of 600.
Data given;
This is the rate or proportion of a substance in the total value and multiplied by 100.
The percentage of sugar in the solution is calculated by
The percentage of sugar in the solution is 1%
Learn more about percentage here;
<u>Answer:</u> The concentration of KOH solution is 1.215 M
<u>Explanation:</u>
For the given chemical equation:
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Hence, the concentration of KOH solution is 1.215 M
3.6 x 10²⁴molecules
Explanation:
Given parameters:
Mass of Na = 275g
Unknown:
Number of molecules of Na₂O =
Solution:
Since sodium is the limiting reactant, we first use it to find the number of mole of the Na₂O and transpose it into finding the number of molecules.
Given equation:
4Na + O₂ → 2Na₂O
Since the equation is balanced, let us find the number of moles of Na;
Number of moles = =
= 11.96moles
From the equation of the reaction;
4 mole of Na produced 2 moles of Na₂O
11.96 moles of Na will produce = 6moles
1 mole of a substance = 6.02 x 10²³ molecules
6 moles of Na₂O = 6 x 6.02 x 10²³ molecules = 3.6 x 10²⁴molecules
learn more:
Number of moles brainly.com/question/1841136
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