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horrorfan [7]
3 years ago
14

What is the hydrogen ion concentration, [H+], of a solution with a pH of 5.43?

Chemistry
1 answer:
grigory [225]3 years ago
6 0

Answer: 3.7 x10−6 Mole per dm^3

Explanation:

pH is the negative logarithm of hydrogen ion concentration in a solution.

So, pH = - log(H+)

Since the solution has a pH of 5.43

5.43 = -log(H+)

To get hydrogen ion concentration, find the Antilog of 5.43

(H+) = Antilog (-5.43)

(H+) = 0.000003715

Then, 0.000003715 in standard form becomes 3.7 x10−6 M

Thus, the concentration of hydrogen ion in the solution is 3.7 x10−6 Mole per dm^3

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Given 0.02 of KF, how many liters of solution are needed to make a 7.2 solution?
Dmitry_Shevchenko [17]

Answer:

1/360

Explanation:

let x = liters

molarity=moles of solute/liters of solution, 7.2=0.02/x or 7.2=(1/50)(1/x), 7.2(50)=(1/x), 360(x)=1, x=1/360

7 0
3 years ago
the trend for ionization energy is a general increase from left to right across a period. However phosphorus is found to have hi
dimaraw [331]
Since phosphorus is in the 5th group it has the ability to gain or lose electrons
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3 years ago
How many liters of O2 gas will be produced at STP from 4 moles of KC1O3
quester [9]

Answer:

V = 134.5 L

Explanation:

Given data:

Number of moles of KClO₃ = 4 mol

Litters of oxygen produced at STP = ?

Solution:

Chemical equation:

2KClO₃  →  2KCl   + 3O₂

Now we will compare the moles of KClO₃ with oxygen.

                    KClO₃        :           O₂

                        2            :           3

                        4            ;          3/2×4 = 6 mol

Litters of oxygen at STP:

PV = nRT

V = nRT/P

V = 6 mol × 0.0821 atm.L/mol.K × 273 K / 1atm

V = 134.5 L / 1

V = 134.5 L

5 0
3 years ago
Please help thank you
maxonik [38]

Answer:

K=1.7x10^{-3}

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by firstly setting up the equilibrium expression for the given reaction, in agreement to the law of mass action:

K=\frac{[NO]^2}{[N_2][O_2]}

Next, we plug in the given concentrations on the data table to obtain:

K=\frac{(0.034)^2}{(0.69)(0.98)}\\\\K=1.7x10^{-3}

Regards!

5 0
2 years ago
Classify a solution with a ph of 13
omeli [17]
Well it's definitely an alkaline solution. 
6 0
3 years ago
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