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FromTheMoon [43]
3 years ago
6

In a chemical reaction, atoms are rearranged to form new substances. This point

Chemistry
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

yes that is right

Explanation:

can i have a brainlist pwease

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Which metal is heaviest ?
const2013 [10]
Titanium is the haviest metal .
8 0
3 years ago
Read 2 more answers
3) How many moles of solute are dissolved in 1.5 L of a 0.80 M solution? * 10 points
Mrrafil [7]

Answer:

1.2

Explanation:

Molarity = moles/volume

to find the moles, you must multiply both sides by volume

so, take 1.5 L * 0.80 M

this equals 1.2 :)

7 0
2 years ago
The solubility of alcohol decrease with increasing numbers of carbon atom explain​
Oxana [17]

The number of carbon atoms in an alcohol affects its solubility in water, as shown in Table 13.3. As the length of the carbon chain increases, the polar OH group becomes an ever smaller part of the molecule, and the molecule becomes more like a hydrocarbon. The solubility of the alcohol decreases correspondingly.

6 0
2 years ago
What electrically neutral atom will have an electron configuration of 1s2 2s2 2p4?
abruzzese [7]

Answer:- oxygen.

Explanations:- The electronic configuration is given and we are asked to figure out the electrically neutral atom that will have the electron configuration, 1s^22s^22p^4 .

The sum of electrons for this electron configuration is 8. If we look at the periodic table then 8 is the atomic number of oxygen.

So, the electrically neutral atom for the given electron configuration is oxygen.

6 0
2 years ago
The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (hooccooh) and must be removed before the st
Andrei [34K]
First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2  so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄      ⇄     H⁺   + HC₂O₄⁻
0.0356 M            0          0
0.0356 - x            x          x
Ka1 = \frac{[H^+][HC2O4^-]}{[H2C2O4]} = x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6
5 0
2 years ago
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