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Fiesta28 [93]
3 years ago
14

The centers of a 15 kg lead ball and a 90 g lead ball are separated by 11 cm. part a what gravitational force does each exert on

the other?
Physics
1 answer:
Black_prince [1.1K]3 years ago
8 0
The gravitational force between the two objects is calculated through the equation,

      F = Gm₁m₂/d²

where F is the gravitational force, G is constant (equal to 6.67 x 10^-11), m₁ and m₂ are masses in kg and d is distance is meters. 

Substituting the known values,

    F = (6.67 x 10^-11)(15 kg)(0.090 kg)/ (0.11 m)²

    F = 7.441 x 10^-9 N

ANSWER: 7.441 x 10^-9 N
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Gina applied 1,780 J of work to move a sofa 3.8 meters. What amount of force did she exert?
Gnoma [55]

Answer:

468.42N

Explanation:

Here,

Work done(W)=1780J

Displacement(s)=3.8m

As we have,

Work=Force×displacement

Now,

\hookrightarrow 1780J=F\times3.8m\\\\\hookrightarrow \frac{1780J}{3.8m} =F\\\\\hookrightarrow F=468.42N

7 0
2 years ago
A merry-go-round rotates from rest with an angular acceleration of 1.45 rad/s2. How long does it take to rotate through (a) the
elena55 [62]

Answer:

(a) t = 5.66 s

(b) t = 8 s

Explanation:

(a)

Here we will use 2nd equation of motion for angular motion:

θ = ωi t + (1/2)∝t²

where,

θ = Angular Displacement = (3.7 rev)(2π rad/1 rev) = 23.25 rad

ωi = initial angular speed = 0 rad/s

t = time = ?

∝ = angular acceleration = 1.45 rad/s²

Therefore,

23.25 rad = (0 rad/s)(t) + (1/2)(1.45 rad/s²)t²

t² = (23.25 rad)(2)/(1.45 rad/s²)

t = √(32.06 s²)

<u>t = 5.66 s</u>

<u></u>

(b)For next 3.7 rev

θ = ωi t + (1/2)∝t²

where,

θ = Angular Displacement = (3.7 rev + 3.7 rev)(2π rad/1 rev) = 46.5 rad

ωi = initial angular speed = 0 rad/s

t = time = ?

∝ = angular acceleration = 1.45 rad/s²

Therefore,

46.5 rad = (0 rad/s)(t) + (1/2)(1.45 rad/s²)t²

t² = (46.5 rad)(2)/(1.45 rad/s²)

t = √(64.13 s²)

<u>t = 8 s</u>

7 0
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