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NISA [10]
3 years ago
11

How can you test to prove that one of your circuits is a series circuit?

Mathematics
1 answer:
choli [55]3 years ago
7 0
If you move one component ( like a light) then no current will pass when you activate the switch.

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If Dante spins the spinner below 75 times, how many times should he expect it to land on "U"?​
Fed [463]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete; So, I will solve making assumptions

Spinner = 10\ segments

U = 1

n=75

Required

Number of times to land on U

First, calculate the theoretical probability of U

Pr(U) = \frac{U}{Spinner}

Pr(U) = \frac{1}{10}

The expected number (E) of time to land on U is then calculated as:

E = Pr(U) * n

E = \frac{1}{10} * 75

E = 0.10 * 75

E = 7.5

Approximate

E = 8

<em>8 times</em>

<em></em>

<em>Follow the above steps, and you will arrive at your answer</em>

3 0
2 years ago
circle 0 shown below has a radius of 27 inches.find to the nearest tenth of a degree the measure of the angle ,x, that forms are
Irina18 [472]

Answer: 29.7 degrees

Step-by-step explanation:

Good, I can see the diagram now!

First calculate circumference of the circle.

C=2πr

C=2π(27)

C=54π in ==> 360 degrees

54π/14=12.11757

360/12.11757=

29.709=29.7 degrees

8 0
2 years ago
Select the correct answer. Which table represents a linear function with a greater y-intercept than that of the function represe
Sladkaya [172]

Answer:

C

Step-by-step explanation:

i just know i guess

5 0
2 years ago
Read 2 more answers
If you flip a fair coin 5 times, and see 3 heads and 2 tails, what fraction of the time will you expect to see a head on the six
Margaret [11]

I hope I'm not wrong here, but B.1/2? Only because its a 50% chance

6 0
3 years ago
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
3 years ago
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