Answer:
0.68 m
Explanation:
Since the volume of water is 310 L, and we know that 1 litre = 1 dm³. So the volume of water is V = 310 dm³. Since this volume of water is the volume of water the cubical steel tank can contain, it equals the volume of the cubical steel tank.
We know that the volume of the cubical steel tank V = L³ where L is the length of side of the cube on the inside.
So the length of side of the cube L = ∛V = ∛310 dm³ = 6.77 dm = 6.77 dm × 1m/10 dm = 0.677 m ≅ 0.68 m
So, the smallest possible inside length of the tank is 0.68 m
You should buy a cool camera you never no what a could ,well say you can write a poem of this
14. D. You just have to compare the graphs!
15. C. This is the only process that produces greenhouse gases! (CO2)
16. D. This fuel source is one of the main culprits for the production of greenhouse gases, and is non-renewable.
I hope this helps you out and I hopes you learned something!
Answer:
Explanation:
Let's assume that an object is launched straight upward in a gravitational field. Its initial kinetic energy is given by
(1)
where m is the mass and v is the initial speed.
As the object goes higher, its kinetic energy decreases and it is converted into gravitational potential energy, since the total mechanical energy (sum of kinetic and potential energy) must remain constant:
At the highest point of the trajectory, the speed of the object is zero (v=0), so the kinetic energy is also zero (K=0), which means that all the kinetic energy has been converted into potential energy:
(2)
where g is the gravitational acceleration and h is the maximum height of the object.
Due to conservation of energy, we can write that (1) and (2) are equal, so:
from which we can derive an expression for the maximum height reached by the object
Con la cinematica podemos encontrar la distancia recorrida antes de detenerse es 169,96 m
Parámetros dados
- velocidad del camión v= 100 km/h
Para encontrar
- La distancia para detenerse
El sistema internacional de medidas (SI) es el sistema que deben tener todas las unidades del ejercicio, este es el primer paso si se tiene una mezcla de unidades
v= 100 km/h ( 1000 m/1 km) ( 1 h/3600 s) = 27,78 m/s
La cinemática estudia el movimiento de los cuerpos, estableciendo relaciones entre la posición, la velocidad y la aceleración
v² = v₀² – 2 a x
Donde v y v₀ son las velocidades inicial y final, a la aceleración del cuerpo y x la distancia recorrida
En este caso como el vehículo se detiene su velocidad final es cero
0= v₀² – 2 a x
x =
Calculemos
x = 27,78² / 2 2,27
x = 169,96 m
En conclusión usando la cinematica podemos encontrar la distancia recorrida antes de detenerse es
x= 169,96 m
Aprender mas acerca de cinemática aquí:
brainly.com/question/11298125