Answer:
171 ft
Explanation:
The distance to be calculated is AB
AB = AC + BC
AC; Cos 60 = AC ÷ 135
AC = 135 cos 60 = 67.5 ft
BC; Cos 40 = BC ÷ 135
BC = 135 cos 40 = 103.416 ft
AB = 67.5 + 103.416 = 170.9159998210 ft
Distance between starting point to end point = 171 ft
To develop this problem it is necessary to apply the concepts related to Wavelength, The relationship between speed, voltage and linear density as well as frequency. By definition the speed as a function of the tension and the linear density is given by

Where,
T = Tension
Linear density
Our data are given by
Tension , T = 70 N
Linear density , 
Amplitude , A = 7 cm = 0.07 m
Period , t = 0.35 s
Replacing our values,



Speed can also be expressed as

Re-arrange to find \lambda

Where,
f = Frequency,
Which is also described in function of the Period as,



Therefore replacing to find 


Therefore the wavelength of the waves created in the string is 3.49m
Answer:
<h2>602.08 N</h2>
Explanation:
The force supplied by the train can be found by using the formula

w is the workdone
d is the distance
From the question we have

We have the final answer as
<h3>602.08 N</h3>
Hope this helps you