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Alchen [17]
3 years ago
8

In a Young's double-slit experiment, a set of parallel slits with a separation of 0.142 mm is illuminated by light having a wave

length of 576 nm and the interference pattern observed on a screen 3.50 m from the slits. (a) What is the difference in path lengths from the two slits to the location of a fourth order bright fringe on the screen? μm (b) What is the difference in path lengths from the two slits to the location of the fourth dark fringe on the screen, away from the center of the pattern? μm
Physics
1 answer:
Alexandra [31]3 years ago
5 0

Answer:

1.152\ \mu m

1.44\ \mu m

Explanation:

d = Gap between slits = 0.142 mm

\lambda = Wavelength of light = 576 nm

L = Distance between light and screen = 3.5 m

m = Order = 2

Difference in path length is given by

\delta=dsin\theta=m\lambda\\\Rightarrow \delta=2\times 576\times 10^{-9}\\\Rightarrow \delta=0.000001152\ m\\\Rightarrow \delta=1.152\times 10^{-6}\ m=1.152\ \mu m

The difference in path lengths is 1.152\ \mu m

For dark fringe the difference in path length is given by

\delta=(m+\dfrac{1}{2})\lambda\\\Rightarrow \delta=(2+\dfrac{1}{2})\times 576\times 10^{-9}\\\Rightarrow \delta=0.00000144\ m=1.44\ \mu m

The difference in path length is 1.44\ \mu m

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Explanation:

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3 years ago
During a golf drive, the angular velocity of the driver is 20 rad/s just before impact with the golf ball. If the distance from
butalik [34]

Answer:

Option B is the correct answer.

Explanation:

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3 years ago
?
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Answer:

Electron shell

Nucleus

Neutrons

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An atom is made up of three fundamental subatomic particles which are the protons, neutrons and electrons.

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5 0
3 years ago
Fill up the blank :- Weight is measured as the downward force of __________.
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<span>Weight is measured as the downward force of gravity.</span>
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3 years ago
A cylindrical fishing reel has a mass of 0.7 kg and a radius of 5.24 cm. A friction clutch in the reel exerts a restraining torq
Korolek [52]

Answer:

Explanation:

moment of inertia of reel = 1/2 mr² , m is mass and r is radius of the reel

= .5 x .7 x .0524²

= 96.1 x 10⁻⁵

If force required be F

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F  x .0524 - 1.88 = moment of inertia x angular acceleration.

F  x .0524 - 1.88 = 96.1 x 10⁻⁵ x 65.7

F  x .0524 - 1.88 = .063

F  x .0524  = .063 + 1.88

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