Answer:
73.33% is the percent yield
Explanation:
Percent yield is defined as:
Actual yield (4.883g) / Theoretical yield * 100
Based on the reaction:
Cu(NO₃)₂(aq) + K₂CO₃(aq) → CuCO₃(s) + 2KNO₃(aq)
<em>1 mole of copper nitrate reacts per mol of potassium carbonate.</em>
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To solve this question we must find limiting reactant. With limiting reactant we can find the theoretical moles of solid produced and its mass as follows:
<em>Moles Cu(NO₃)₂:</em>
0.1639L * (0.329mol / L) = 0.0539 moles
<em>Moles K₂CO₃:</em>
0.1639L * (0.528mol / L) = 0.0865 moles
As the reaction is 1:1, the limiting reactant is Cu(NO₃)₂.
1 mol of Cu(NO₃)₂ produces 1 mol of CuCO₃. That means theoretical moles produced are 0.0539 moles. And the mass is:
<em>Mass CuCO₃ -Molar mass: 123.55g/mol-</em>
0.0539 moles * (123.55g / mol) = 6.659g of CuCO₃ is the theoretical mass
And percent yield:
4.883g / 6.659g * 100
<h3>73.33% is the percent yield</h3>
False, if they were closer together they would be more likely to experience the same things in the fetus.
Answer:
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Explanation:
Answer:
Explanation:
The formula for molality is:
There are 0.210 moles of KBr and 0.075 kilograms of pure water.
Substitute the values into the formula.
Divide.
The molality is <u>2.8 moles per kilogram</u>