Answer:
Maximum torque on the wire is 
Explanation:
It is given that,
Diameter of the wire, d = 11.1 cm = 0.111 m
Radius of wire, r = 0.0555 m
Magnetic field, 
Current, I = 5 A
We need to find the maximum torque on the wire. Torque is given by :

Torque is maximum when, 



or

So, the maximum toque on the wire is
. Hence, this is the required solution.
Answer:
a. TRUE
Explanation:
When a satellite is launched to orbit around earth, it has to produce its own artificial gravity by performing rotations. The frequency of this rotation is given by the following formula:
f = √[ac/4πR²]
where,
f = frequency
ac = centripetal acceleration
R = Radius of the satellite
Therefore, it is clear from this formula that the frequency of rotation of the satellite is independent of its height above the surface of earth. So, the correct option is:
<u>a. TRUE</u>
Answer:
The time is
Explanation:
From the question we are told that
The height of the platform where the ball was dropped from is s = 215 m
The acceleration due to gravity is 
Generally from kinematic equations

Here u is the initial velocity of the ball and the value is u = 0 m/s given that the ball was at rest before it was dropped
So

=> 
=> 
=>
Given,
The initial inside diameter of the pipe, d₁=4.50 cm=0.045 m
The initial speed of the water, v₁=12.5 m/s
The diameter of the pipe at a later position, d₂=6.25 cm=0.065 m
From the continuity equation,

Where A₁ is the area of the cross-section at the initial position, A₂ is the area of the cross-section of the pipe at a later position, and v₂ is the flow rate of the water at the later position.
On substituting the known values,

Thus, the flow rate of the water at the later position is 5.99 m/s