Answer:
7.0N
Explanation:
F=ma
v2=u2+2as
25=0+20a
a=1.25m/s2
F=0.4×1.25
Fn=5N
F=12
12-5=Ff
=7.0N
0.2 T
40g
20g range > 1.0cm
Therefore,
40g range > 2.0cm
(amount of heat)Q = ? , (Mass) m= 4 g , ΔT = T f - T i = 180 c° - 20 °c = 160 °c ,
Ce = 0.093 cal/g. °c
Q = m C ΔT
Q = 4 g × 0.093 cal/g.c° × ( 180 °c- 20 °c )
Q= 4×0.093 × 160
Q = 59.52 cal
I hope I helped you^_^
Beige to black.
:)
