A horizontal force of 12 Newtons is applied to a 4.0 kg box that slides on a horizontal surface. The box starts from rest moves
a horizontal distance of 10 meters and obtains a velocity of 5.0 m/s. The surface has friction. The friction force is
Group of answer choices
4.9 N.
6.0 N.
7.0 N.
6.5 N.
1 answer:
Answer:
7.0N
Explanation:
F=ma
v2=u2+2as
25=0+20a
a=1.25m/s2
F=ma
F=0.4×1.25
Fn=5N
F=12
12-5=Ff
=7.0N
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