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Valentin [98]
3 years ago
5

The contents of the cylinder is then entirely transfered to a partially filled holding tank of volume 10,000 L originally at pre

sure 2 atm and 300 K. What is the new pressure in the holding tank at 300 K?
Physics
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

The new pressure in the holding tank is 2 atm.

Explanation:

Given that,

Volume = 10000 L

Initial pressure 2 atm

Initial temperature = 300 k

We need to calculate the new pressure

Using equation of ideal gas

PV=RT

R=\dfrac{PV}{T}

Where,P = pressure

T = temperature

V = volume

R = constant

Put the value into the formula

Volume of gas are remain constant

So,

\dfrac{P_{i}V}{T_{i}}=\dfrac{P_{f}V}{T_{f}}

\dfrac{2\times10000}{300}=\dfrac{P_{f}\times10000}{300}

P_{f}=2\ atm

Hence, The new pressure in the holding tank is 2 atm.

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A sound wave has a speed of 340 m/s and a frequency of 1000 hz. The period of the sound is closest to?
harina [27]
<h2>Relationship Between Frequency and Period</h2>

The frequency and the period are inversely proportional.

f=\dfrac{1}{T} where T is the period

<h2>Solving the Question</h2>

We're given:

  • <em>v</em> = 340 m/s
  • <em>f</em> = 1000 Hz

Because the frequency and the period are reciprocals of each other, we can find the period of the sound by finding the reciprocal of the frequency:

T=\dfrac{1}{1000}

<h2>Answer</h2>

T=\dfrac{1}{1000}

6 0
2 years ago
) a 1.0 kilogram laboratory cart moving with a velocity of 0.50 meter per second due east collides with and sticks to a similar
ZanzabumX [31]
Momentum would be the same before and after the collision
 Before the collision:
 Momentum of the single cart: 1 * 0.50 = 0.50
 After the collision
 velocity = 0.25m / s
 1 * 0.25 + 1 * 0.25 =
 0.25 * (1 + 1) =
 0.25 * 2 =
 0.50
 Now new momentum will be 0.5
 answer
 the same before and after the collision
4 0
4 years ago
Read 2 more answers
(b) The density of aluminum is 2.70 g/cm3. The thickness of a rectangular sheet of aluminum foil varies
vekshin1

Answer:

(i) 22.48 cm^3

(ii) 1.5 mm

Explanation:

Let t be the average thickness of the sheet.

Given that:

Density of the aluminum sheet is 2.70 g/cm^3

Mass of sheet = 60.7 g

Length of sheet  = 50.0 cm

Width of sheet  = 30.0 cm

(i) Using, Density=Mass/Volume

\Rightarrow \text{Volume}=\frac{\text{Mass}}{\text{Density}}

\Rightarrow \text{Volume}=\frac{60.7}{2.7}=22.48 cm^3

Hence, the volume of the sheet is 22.48 cm^3.

(ii) Now, as this aluminum sheet is in the shape of a cuboid, so the volume of the sheet is

\text{Volume}=\text{Length}\times\text{Width}\times\text{Thickness}

\Rightarrow 22.48=50\times 30 \times w

\Rightarrow w=\frac{22.48}{50\times 30}=0.015 cm

Hence, the average thickness of the sheet is 1.5 mm.

6 0
3 years ago
A train moves at constant velocity of 90km/h. How far will it go in 0.25h.
enot [183]
In a quarter of an hour it will travel 1/4 x 90 = 22.5Km
8 0
3 years ago
Observe: Click Reset. Turn on Show velocity vector and Show velocity components. Set vinitial to 50 m/s and set θ to 45.0 degree
Kobotan [32]

Answer:

v_y = v_{oy} - g t

where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses

Explanation:

In this exercise you are asked to observe the change in velocity in a projectile launch.

If we assume that the friction force is small, the velocity in the x-axis must be constant

         vₓ = v₀ₓ

Therefore, the arrow (red) that represents this movement must not change in magnitude.

In the direction of the y axis, the acceleration of gravity is acting, so the magnitude of the velocity in this axis changes

         v_y = v_{oy} - g t

where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses

7 0
3 years ago
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