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Mashutka [201]
3 years ago
13

The distance from the bottom of the objective lens to the surface of the slide is called the

Physics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

It's called the working distance .

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Describe what long sight is and how it is corrected with a lens
o-na [289]

If long sight means farsighted, then here's your answer:

Farsightedness is when the lens has difficulty focusing on nearby objects. Sufferers must squint to see the nearby objects. Reading, writing, and drawing for longer periods of time can cause eyestrain and headache.

Being farsighted can be corrected with prescription glasses or contact lenses or surgery.

7 0
4 years ago
Compare and Contrast electromagnetic waves to infer the relationship between frequency, energy, and wavelength.
natta225 [31]

Answer:

Explanation:This question is simply asking you to describe the following equations:

E = hv

v = c/L

E = hc/L

where E is the energy, h is Planck's constant, v is the frequency, c is the speed of light and L is the wavelength.

By looking at the equations you should be able to tell what the relationships between energy, frequency and wavelength are. If you are having difficulty describing them, then create a table with actual values and see what happens to the energy as you increase or decrease the frequency and/or wavelength.

6 0
2 years ago
Are all the craters the same?​
KiRa [710]

Answer:

no because there are large ones middieum and small but they're mostly large

Explanation:

8 0
3 years ago
What is the square root of 25x10^12
kirill115 [55]

\sqrt{25 \times 10^{12} }

In order to find it's square root, we could make it into two square roots.

\sqrt{25 \times 10^{12} } = \sqrt{25} \times \sqrt{10^{12}}

Let us find the square roots of both radicals seprately.

\sqrt{25} =\sqrt{5*5}=5

Each  pair  of a number inside square root gives a number out .

\sqrt{10^{12}} = \sqrt{10*10*10*10*10*10*10*10*10*10*10*10}   \ \ ( \ makes \ 6 \ pairs \ of \ 10 )

\sqrt{10*10*10*10*10*10*10*10*10*10*10*10} = 10*10*10*10*10*10

= 10^6.

Therefore,

\sqrt{25 \times 10^{12} }=\sqrt{25} \times \sqrt{10^{12}}={5 \times 10^6}

\sqrt{25 \times 10^{12} } = {5 \times 10^6}

7 0
3 years ago
Suppose you are asked to find the amount of time t, in seconds, it takes for the turntable to reach its final rotational speed.
Annette [7]

Answer:

option (D)

Explanation:

Here initial rotation speed is given, final rotation speed is given and asking for time.

If we use

A) θ=θ0+ω0t+(1/2)αt2

For this equation, we don't have any information about the value of angular displacement and angular acceleration, so it is not useful.

B) ω=ω0+αt

For this equation, we don't have any information about angular acceleration, so it is not useful.

C) ω2=ω02+2α(θ−θ0)

In this equation, time is not included, so it is not useful.

D) So, more information is needed.

Thus, option (D) is true.

5 0
3 years ago
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