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lana [24]
3 years ago
14

What is the square root of 25x10^12

Physics
1 answer:
kirill115 [55]3 years ago
7 0

\sqrt{25 \times 10^{12} }

In order to find it's square root, we could make it into two square roots.

\sqrt{25 \times 10^{12} } = \sqrt{25} \times \sqrt{10^{12}}

Let us find the square roots of both radicals seprately.

\sqrt{25} =\sqrt{5*5}=5

Each  pair  of a number inside square root gives a number out .

\sqrt{10^{12}} = \sqrt{10*10*10*10*10*10*10*10*10*10*10*10}   \ \ ( \ makes \ 6 \ pairs \ of \ 10 )

\sqrt{10*10*10*10*10*10*10*10*10*10*10*10} = 10*10*10*10*10*10

= 10^6.

Therefore,

\sqrt{25 \times 10^{12} }=\sqrt{25} \times \sqrt{10^{12}}={5 \times 10^6}

\sqrt{25 \times 10^{12} } = {5 \times 10^6}

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Answer:

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Density = mass/volume

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mA = 2.784 × 10^11 km3 × dA ...equation 1

mB= 1.437 × 10^12km3 × dB... equation 2

but mA/mB= 0.96

mA = 0.96 × mB

substitute for mA in equation 1

0.96 × mB = 2.784 × 10^11 x dA equation 3

Substitute for mB in equation 3..

(refer to equation 2)

0.96×1.437×10^12 × dB = 2.784 × 10^11 × dA .....equation 4

divide through by the coefficient of dA

dA = (0.96×1.437×10^12×dB)/(2.784 × 10^11)

divide through by dB

dA/dB = 4.955

therefore, the ratio of dA to dB is 5/1

Therefore, the mean density of A is almost five times that of B

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