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lana [24]
3 years ago
14

What is the square root of 25x10^12

Physics
1 answer:
kirill115 [55]3 years ago
7 0

\sqrt{25 \times 10^{12} }

In order to find it's square root, we could make it into two square roots.

\sqrt{25 \times 10^{12} } = \sqrt{25} \times \sqrt{10^{12}}

Let us find the square roots of both radicals seprately.

\sqrt{25} =\sqrt{5*5}=5

Each  pair  of a number inside square root gives a number out .

\sqrt{10^{12}} = \sqrt{10*10*10*10*10*10*10*10*10*10*10*10}   \ \ ( \ makes \ 6 \ pairs \ of \ 10 )

\sqrt{10*10*10*10*10*10*10*10*10*10*10*10} = 10*10*10*10*10*10

= 10^6.

Therefore,

\sqrt{25 \times 10^{12} }=\sqrt{25} \times \sqrt{10^{12}}={5 \times 10^6}

\sqrt{25 \times 10^{12} } = {5 \times 10^6}

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You and your best friend are bored on a saturday afternoon and decide to measure the impulse acting on a basketball when it boun
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Answer:

v = √(2gh)

Assuming g = 9.81m/s^2

v = √(19.62h)

Explanation:

Let v represent the speed of the ball just before it collide with the ground.

Applying the equation of motion;

v^2 = u^2 + 2as

Where;

v = final velocity

u = initial speed = 0 (starting from rest)

a = acceleration= g acceleration due to gravity

s = distance covered = h

So, substituting the values;

v^2 = 0^2 + 2gh

v^2 = 2gh

v = √(2gh)

Assuming g = 9.81m/s^2

v = √(19.62h)

7 0
3 years ago
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a car accelerates from 2 m/s to 28m/s at a constant rate of 3 m/s^2. How far does it travel while accelerating?
xxTIMURxx [149]

Answer:

Distance, S = 130m

Explanation:

Given the following data;

Initial velocity = 2m/s

Final velocity = 28m/s

Acceleration = 3m/s²

To find the distance, we would use the third equation of motion.

V² = U² + 2aS

Substituting into the equation, we have;

28² = 2² + 2*3*S

784 = 4 + 6S

6S = 784 - 4

6S = 780

S = 780/6

Distance, S = 130m

3 0
3 years ago
From the anatomical position, the digits are ____ to the brachium.
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A I believe if not I’m sorry
4 0
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An unwary football player collides with a padded goalpost while running at a velocity of 9.50 m/s and comes to a full stop after
Amanda [17]

Answer:

(a) The collision lasts for 0.053 s.

(b) The deceleration is 180.5 m/s².

Explanation:

Given:

Initial velocity of the player (u) = 9.50 m/s

Final velocity of the player (v) = 0 m/s (Comes to a stop)

Displacement of the player (S) = 0.250 m

We know that, using equation of motion relating displacement (S), acceleration (a), initial velocity (u) and final velocity (v), we have:

v^2=u^2+2aS

Expressing in terms of 'a', we get:

a=\frac{v^2-u^2}{2S}

Plug in the given values and solve for 'a'. This gives,

a=\frac{0-9.50^2}{2\times 0.250}\\\\a=\frac{-90.25}{0.5}=-180.5\ m/s^2

Therefore, the acceleration of the player is -180.5 m/s². So, the deceleration is 180.5 m/s².

Now, using the first equation of motion, we have:

v=u+at\\\\t=\frac{v-u}{a}

Plug in the given values and solve for 't'. This gives,

t=\frac{0-9.5}{-180.5}\\\\t=0.053\ s

Therefore, the the collision will last for 0.053 s.

(a) The collision lasts for 0.053 s.

(b) The deceleration is 180.5 m/s².

8 0
3 years ago
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TEA [102]

Answer:

4 m/s or 4 meters per second.

Explanation:

In order to calculate the speed of wave, you multiply the wavelength in meters and the frequency of the Wave in Hertz. 2 times 2 equals 4. The wave speed is always in m/s considering that the wavelength is also in meters.

7 0
4 years ago
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