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IgorC [24]
3 years ago
8

What determines the pitch of a sound wave

Physics
2 answers:
saveliy_v [14]3 years ago
4 0
Frequency of the wave " the loudness"
Likurg_2 [28]3 years ago
4 0
The pitch of a sound wave is determined by the frequency.

A higher frequency leads to a higher pitch, while a lower frequency leads to a lower pitch.
You might be interested in
My mass is 65 kg and on Earth this equals a weight of 640 N, but on the moon where gravity is 1.7 m/s² my
Helen [10]

Your weight on the moon given the data from the question is 110.5 N

<h3>Definition of mass and weight </h3>

Mass is simply defined as the quantity of matter present in an object. The mass of an object is constant irrespective of the location of the object.

Weight is simply defined as the gravitational pull on an object. The weight of an object varies from place to place due to gravity.

<h3>Relationship between mass and weight </h3>

Mass and weight are related according to the following equation

Weight (W) = mass (m) × Acceleration due to gravity (g)

<h3>How to determine the weight on the moon</h3>
  • Mass (m) = 65 Kg
  • Acceleration due to gravity on the moon (g) = 1.7 m/s²
  • Weight (W) =?

W = mg

W = 65 × 1.7

W = 110.5 N

Learn more about mass and weight:

brainly.com/question/14684564

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4 0
1 year ago
A 25 kg box sliding to the left across a horizontal surface is brought to a halt in a distance of 15 cm by a horizontal rope pul
Nuetrik [128]
B)is pills everything to the surface of the earth not sure about A
5 0
3 years ago
The radial velocity method preferentially detects: Choose one: A. all of the above described planets equally well. B. small plan
Zina [86]

The radial velocity method preferentially detects large planets close to the central star

  • what is the Radial velocity:

The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.

This is due to the fact that low mass stars are more affected by the gravitational tug of planets.

When a planet orbits around a star, the star wobbles a little.

From this, we can determine the mass of the planet and its distance from the star.

hence we can say that,

option D is correct.

The radial velocity method preferentially detects large planets close to the central star

Learn more about radial velocity here:

<u>brainly.com/question/13117597</u>

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5 0
1 year ago
The left side of the lever was forced down 10 inches in order to raise the rock 7 inches. The ideal mechanical advantage is
Yanka [14]

Answer:

1.42

Explanation:

<em> got it right on my homework </em>

6 0
2 years ago
The gravitational potential energy of a particle of mass m moving under the influence of a fixed mass M is given by - , where G
djverab [1.8K]

-GMm/2r is the total energy of the mass m if it is in a circular orbit about mass M.

Given

A particle of mass m moving under the influence of a fixed mass's M, gravitational potential energy of formula  -GMm/r, where r is the separation between the masses and G is the gravitational constant of the universe.

As the Gravity Potential energy of particle = -GMm/r

Total energy of particle = Kinetic energy + Potential Energy

As we know that

Kinetic energy = 1/2mv²

Also, v is equals to square root of GM/r

v = √GM/r

Put the value of v in the formula of kinetic energy

We get,

Kinetic Energy = GMm/2r

Total Energy = GMm/2r + (-GMm/r)

                     = GMm/2r - GMm/r

                     = -GMm/2r

Hence, -GMm/2r is the total energy of the mass m if it is in a circular orbit about mass M.

Learn more about Gravitational Potential Energy here brainly.com/question/15896499

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3 0
1 year ago
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