All categories

3 years ago

What is question 22?

Physics

2 answers:

zalisa [80]3 years ago

5 0

The object moves 18 meters in 6 seconds (10 - 4).

18m/6s= 3m/s

Answer "A"

Fynjy0 [20]3 years ago

4 0

the answer is a!! its pretty simple I just read the graph.

You might be interested in

Will mark as BRAINLIEST....... The Displacement x of particle moving in one dimension under the action of constant force is rela

pentagon [3]

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

$x=4t^3+3t^2-5t+2$

Where,

x is in meters and t is in sec

We know that,

Velocity,

$v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5$

(a) i. t = 2 s

$v=12(2)^2+6(2)-5=55\ m/s$

At t = 4 s

$v=12(4)^2+6(4)-5=211\ m/s$

(b) Acceleration,

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6$

Pu t = 3 s in the above equation

So,

$a=24(3)+6\\\\a=78\ m/s^2$

Hence, this is the required solution.

3 0

3 years ago

An ant is on the pendulum bob of the clock. What would be the displacement in one time period?

Dennis_Churaev [7]

At the end of one full time period, the ant has returned to where it was at the beginning of the time period. Its displacement is <em>zero</em>.

6 0

3 years ago

Suppose an event is measured to be at a = (0,-2, 3, 5) in one reference frame. Find the components of this event in another refe

LenaWriter [7]

Answer:

The components of the moving frame is (8.07c, -2, 3, 9.493)

Solution:

As per the question:

Velocity of moving frame w.r.t original frame $v_{m}$ 0.85c

Point 'a' of an event in one reference frame corresponds to the (x, y, z, t) coordinates of the plane

a = (0, - 2, 3, 5)

Now, according the the question, the coordinates of moving frame, say (X, Y, Z, t'):

New coordinates are given by:

X = $\frac{x - v_{m}t}{\sqrt{1 - \frac{v_{m}^{2}}{c^{2}}}}$

X = $\frac{0 - 0.85c\times 5}{\sqrt{1 - \frac{(0.85c)^{2}}{c^{2}}}}$

X = $8.07 c$

Now,

Y = y = - 2

Z = z = 3

Now,

$t' = \frac{t - \frac{vx}{c}^{2}}{\sqrt{1 - (\frac{v}{c})^{2}}}$

$t' = \frac{5 - 0}{\sqrt{1 - (\frac{0.85c}{c})^{2}}} = 9.493 s$

4 0

3 years ago

two thermometers, calibrated in celsius and fahrenheit respectively, are put into a liquid. the reading on the fahrenheit scale

Viefleur [7K]

Two thermometers, calibrated in celsius and fahrenheit respectively, are put into a liquid. the reading on the fahrenheit scale is four times the reading on the celsius scale. the temperature of the liquid is:

6 0

3 years ago

Explain why the amplitude of the wave did not change when you increased the frequency of the stimulation. how well did the resul

barxatty [35]

The amplitude did not change when the recurrence was expanded on the grounds that the long headstrong time of the heart forestalls adjustment. It is the most extreme removal or separation moved by a point on a vibrating body or wave measured from its balance position. It is equivalent to the one-a large portion of the length of the vibration way.

5 0

3 years ago