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3 years ago

How much work was done on a 45 kg weight when lifted 1.4 meters in the air?

Physics

1 answer:

BabaBlast [244]3 years ago

8 0

Explanation:

w = f x d

45 x 1.4 = 630j

to get newton's do 45 x gravitation field strength

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When a liquid is at its boiling point there is an increase in potential energy, kinetic energy, or all of the above

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Answer:potential energy

Explanation:

When a liquid is at it boiling point, there is increase in it potential energy

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3 years ago

What does a spring balance measure

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The spring balance provides a mass measurement

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3 years ago

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2 years ago

Starting from rest, a small block of mass m slides frictionlessly down a circular wedge of mass M and radius R which is placed o

guapka [62]

Answer:

Part a)

$V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

$v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

$y_{cm} = \frac{mR}{m + M}$

Explanation:

PART A)

As we know that there is no external force on the system of two masses in horizontal direction

So here the two masses will have its momentum conserved in horizontal direction

So we have

$mv + MV = 0$

Also we know that here no friction force on the system so total energy will always remains conserved

So we have

$\frac{1}{2}mv^2 + \frac{1}{2}MV^2 = mgR$

now we have

$\frac{1}{2}m(\frac{MV}{m})^2 + \frac{1}{2}MV^2 = mgR$

$\frac{1}{2}MV^2(\frac{M}{m} + 1) = mgR$

so we have

$V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

and another block has speed

$v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

$y_{cm} = \frac{mR}{m + M}$

7 0

3 years ago

A copper wire has a length of 1.50 m and a cross sectional area of 0.380 mm2. If the resistivity of copper is 1.70 ✕ 10−8 Ω · m

sweet [91]

Answer: 1.044 E -17 A

Explanation:

L =1.50m

A = 0.380mm = 3.8E- 7

Resistivity p =1.70 E-8

R =pl/A

R = 1.70 E-8 × 1.5/ 3.8 E-7

R = 6.71 E-16 ohms

V = IR

0.700 = I × 6.71 E-16

I =1.044E-17 A

5 0

3 years ago