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4 years ago

5

How would the Earth move if the sun (including its gravity) suddenly disappeared? Explain your answer.

1 answer:

daser333 [38]4 years ago

5 0

It would float outward as all space is expanding from the center constantly. of by some chance it for caught in the orbit of another celestial body with huge mass it may orbit that, bur other wise it would just push outward from the center of the universe theoretically the big bang

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Two 65.0 kg ice skaters are standing 2.00 m away from each other in the ice. What is the gravitational attraction between the tw

Paladinen [302]

Answer:

A) 7×10⁻⁸ N

Explanation:

r = Distance between the two skaters = 2 m

m₁ = m₂ = Mass of the two skaters = 65 kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

From Newton's Law of Universal gravity

$F=G\frac{m_1m_2}{r^2}\\\Rightarrow F=6.67\times 10^{-11} \frac{65\times 65}{2^2}\\\Rightarrow F=7.045\times 10^{-8}\ N$

∴ Force of gravity between the two skaters is 7×10⁻⁸ N

7 0

4 years ago

Select all of the examples of an acid.

Alla [95]

All i know is
- baking soda
-lemon
-vinegar
-bleach

8 0

3 years ago

What is the total resistance of a 6 ohm and a 8 ohm resistor connected in series?<br> (1 Point)

Oksanka [162]

Answer:

Total Resistance in circuit is Fourteen Ohms <u>(14 Ω).</u>

<u></u>

Explanation:

How do we know, if the resistors are connected in series, the total resistance is the <u>sum of all the resistors.</u>

(Important: The total resistance can only be added just when the resistors are <u>connected in series</u>)

Then, total resistance (<em>TR </em>) is the sum of all resistors (<em>T1 + T2</em>, in this case)

TR = T1 + T2

According to problem data, we have:

TR = 8 Ω + 6 Ω

TR = 14 Ω

║Sincerely, ChizuruChan║

4 0

3 years ago

Which of the following is WRONG?

iren2701 [21]

It’s D the time period within pendulums are constant, distance is always measured with kilometers within cities and basic unit is always seconds.

3 0

3 years ago

Read 2 more answers

A scuba tank, when fully submerged, displaces 16.7 L of seawater. The tank itself has a mass of 13.4 kg and, when "full," contai

meriva

Answer:

$m = 17.87 kg$

Explanation:

As we know that tank itself has mass given as 13.4 kg

so it is given as

$m_1 = 13.4 kg$

also the tank contains air in it and the mass of air inside the tank is also given as 4.47 kg

so it is

$m_2 = 4.47 kg$

so total mass of the tank is the mass of the empty tank and mass of air in the tank

$m = m_1 + m_2$

$m = 13.4 + 4.47$

$m = 17.87 kg$

3 0

3 years ago