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garri49 [273]
3 years ago
10

Which of these properties of an object best quantifies its inertia: velocity, acceleration, volume, mass, or temperature?

Physics
1 answer:
LuckyWell [14K]3 years ago
3 0

Answer:

Mass

Explanation:

Inertia is essentially an object's tendency to stay in motion or at rest unless it is forced to do otherwise (pun intended). It only makes sense to me that mass would best quantify an object's inertia, because an object with more mass would be harder to move and/or stop from moving.

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A 2000 kg car is moving at 15 m/sec when it collides with a 1200 kg car sitting still. Briefly compare the impulse imparted on t
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Answer:

The 1200 kg car.

Explanation:

The 1200 kg car had bo momentum at the initial stage of the journey because it wasn't on motion. But after collision with the 2000 kg car it gained alot of momentum.

4 0
3 years ago
A singly charged positive ion that has a mass of 6.07 ? 10-27 kg moves clockwise with a speed of 1.18 ? 104 m/s. the positively
mezya [45]
B = 0.018 T Ans, 

Since, it is moving in a circular path, thus, centripetal force will act on it i.e.
F =  \frac{ mv^{2} }{r}
where, m is the mass of the object, v is the velocity and r is the radius of circular path.

And, since a positive charge is moving, it will create magnetic force which is equal to F = qvB
where q is the charge, v is the velocity of the particle and B is the magnetic field.
Now, the two forces will be equal,
i.e. \frac{ mv^{2} }{r} = qvB
⇒ \frac{ mv }{r} = qB
⇒B = \frac{ mv }{qr}
<span>putting the values, we get,
</span>
use q = 1.6 * 10^ -19
⇒ B = 0.018 T

8 0
3 years ago
How much more intense is sound at 40 db than sound at zero db?
Gnesinka [82]
It is 10^4 times the intensity at 0 db
3 0
3 years ago
A 72.0-kg skydiver is falling at a terminal velocity of 79.0 m/s. Which equation should be used to calculate the diver’s kinetic
rodikova [14]

Answer:

KE= 1/2 * mass * Velocity^2

Explanation:

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4 0
3 years ago
A pendulum consisting of a 0.5 kg mass tied to a 0.3 m string is set into oscillation at the same moment that a stone is dropped
lara31 [8.8K]

Answer:

2.72 cycles

Explanation:

First of all, let's find the time that the stone takes to reaches the ground. The stone moves by uniform accelerated motion with constant acceleration g=9.8 m/s^2, and it covers a distance of S=44.1 m, so the time taken is

S=\frac{1}{2}at^2\\t=\sqrt{\frac{2S}{a}}=\sqrt{\frac{2(44.1m)}{9.8 m/s^2}}=3 s

The period of the pendulum instead is given by:

T=2 \pi \sqrt{\frac{L}{g}}=2 \pi \sqrt{\frac{0.3 m}{9.8 m/s^2}}=1.10 s

Therefore, the number of oscillations that the pendulum goes through before the stone hits the ground is given by the time the stone takes to hit the ground divided by the period of the pendulum:

N=\frac{t}{T}=\frac{3 s}{1.10 s}=2.72

6 0
3 years ago
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