Answer:
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Explanation:
The de - acceleration of bullet from 360 m/s after it struck the tree trunk and was brought to rest is -152.54 x 10⁴ m/s².
<h3>What is Acceleration in Kinematics?</h3>
Acceleration is defined as the rate of change of velocity with respect to time. Mathematically -
<h3>a = Δv/Δt</h3>
Given is a bullet initially travelling at 360 m/s struck into a tree trunk 8.5 cm inside and comes to rest. From this, we can write
initial velocity [u] = 360 m/s
final velocity [v] = 0 m/s
distance travelled [d] = 8.5 cm = 0.085 m
The time span after which bullet comes to rest will be -
Δt = d/u
Δt = 0.085/360 = 2.36 x 10 ⁻⁴ seconds
a = Δv/Δt
Δv = 0 - 360 = - 360 m/s
a = (v - u)/Δt
a = - 360/(2.36 x 10 ⁻⁴)
a = - 152.54 x 10⁴ m/s²
Therefore, the de - acceleration of bullet from 360 m/s after it struck the tree trunk and was brought to rest is -152.54 x 10⁴ m/s².
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Answer: 0.137 m
Explanation:
Given
Mass of brick, m = 3 kg
Angle of inclination, Φ = 34°
Force constant of the spring, k = 120 N/m
The force of the brick, F can be gotten using the relation
F = mg
F = 3 * 9.8
F = 29.4 N
Now, the force parallel to the incline, F(p) can be gotten using the formula,
F(p) = F sinΦ, so that
F(p) = 29.4 * sin 34
F(p) = 29.4 * 0.559
F(p) = 16.4 N
The stretch distance then is,
d = F(p) / k * 1 m
d = 16.4 / 120
d = 0.137 m
Thus, the spring stretched by a distance of 0.137 m
Answer:
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