Answer:
0.625 moles of CO₂ can be produced by this reaction.
27.5 g of CO₂
Explanation:
A reaction where CO₂ can be produced is combustion.
The reactants are methane (in this case) and oxygen, while the products will be CO₂ and H₂O.
The balanced reaction is: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)
We assume the oxygen is in excess, so the methane gas, is the limiting reagent.
We convert the mass to moles (mass / molar mass) → 10 g / 16 g/mol = 0.625 moles
According to stoichiometry, 1 mol of methane can produce 1 mol of CO₂. Therefore If we have 0.625 moles of CH₄ we produce 0.625 moles of CO₂. Ratio is 1:1.
Let's convert the moles to mass → (mol . molar mass) =
0.625 mol . 44 g/mol = 27.5 g
