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asambeis [7]
4 years ago
13

How much CO2 is produced from 10g of CH4?

Chemistry
1 answer:
prohojiy [21]4 years ago
3 0

Answer:

0.625 moles of CO₂ can be produced by this reaction.

27.5 g of CO₂

Explanation:

A reaction where CO₂ can be produced is combustion.

The reactants are methane (in this case) and oxygen, while the products will be CO₂ and  H₂O.

The balanced reaction is: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

We assume the oxygen is in excess, so the methane gas, is the limiting reagent.

We convert the mass to moles (mass / molar mass) → 10 g / 16 g/mol = 0.625 moles

According to stoichiometry, 1 mol of methane can produce 1 mol of CO₂. Therefore If we have 0.625 moles of CH₄ we produce 0.625 moles of CO₂. Ratio is 1:1.

Let's convert the moles to mass → (mol . molar mass) =

0.625 mol . 44 g/mol = 27.5 g

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A sample of helium gas has a volume of 2.75 L at STP. How many grams of He are present?
il63 [147K]
Molar mass He = 4.0 g/mol

1 mole --------- 22.4 L ( at STP )
? mole ---------- 2.75 L

2.75 x 1 / 22.4 => 0.1227 moles

1 mole He ------------ 4.0 g
0.1227 moles --------- ?

0.1227 x 4.0 / 1 => 0.4908 g of He

hope this helps!
4 0
3 years ago
Which energy changes are associated with a liquid boiling?
Delvig [45]

Answer: Energy is absorbed, and kinetic energy increases

Explanation: Boiling is the phenomenon in which liquid is converted to gaseous state.

Thus in order to break the inter molecular forces of attraction present in a liquid, energy is required and thus the process is endothermic in nature.

As the molecules absorb energy, the kinetic energy of the molecules increases and they start moving faster and more randomly and convert into gaseous state.

7 0
3 years ago
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Glenn is heating water in a teakettle. The hotter water at the bottom of the kettle rises. The cooler water near the top sinks a
alexandr402 [8]
B. convection

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5 0
3 years ago
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For the reaction: CO(g) + H2O(g) ⇌ CO2(g) + H2(g) the value of Kc is 1.845 at a specific temperature. We place 0.500mol CO and
patriot [66]

Answer:

Explanation:

In the equilibrium:

CO(g) + H₂O(g) ⇄ CO₂(g) + H₂(g)

Kc is:

Kc = 1.845 = [CO₂] [H₂] / [CO] [H₂O]

<em>Where [] are equilibrium concentrations of each species</em>

<em />

Initial concentrations:

[CO] = 0.500mol / 1.00L = 0.500M

[H₂O] = 0.500mol / 1.00L = 0.500M

In equilibrium, concentrations will be:

[CO] = 0.500M - X

[H₂O] = 0.500M - X

[CO₂] = X

[H₂] = X

<em>Where X is reaction coordinate. The amount of reactant that reacts producing products.</em>

<em />

Replacing in Kc expression:

1.845 = [CO₂] [H₂] / [CO] [H₂O]

1.845 = [X] [X] / [0.500M - X] [0.500M - X]

1.845 = X² / X² - X + 0.25

1.845X² - 1.845X + 0.46125 = X²

0.845X² - 1.845X + 0.46125 = 0

Solving for X:

X = 0.288M; Right solution

X = 1.9M; False solution: Produce negative concentrations.

Replacing, equilibrium concentrations are:

[CO] = 0.500M - X = 0.212M

[H₂O] = 0.500M - X = 0.212M

[CO₂] = X = 0.288M

[H₂] = X = 0.288M

3 0
3 years ago
How many moles of KNO3 are in 37.5 mL of .445 M KNO3?
Kitty [74]
Convert 50mL to liters by dividing it by 1000 to get your liters value which should be 0.05 L
Now your formula is .20 = x/0.05
Solve for x to get your mol value and you should get 0.01 mol
3 0
4 years ago
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