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3 years ago

How much CO2 is produced from 10g of CH4?

Chemistry

1 answer:

prohojiy [21]3 years ago

3 0

Answer:

0.625 moles of CO₂ can be produced by this reaction.

27.5 g of CO₂

Explanation:

A reaction where CO₂ can be produced is combustion.

The reactants are methane (in this case) and oxygen, while the products will be CO₂ and H₂O.

The balanced reaction is: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

We assume the oxygen is in excess, so the methane gas, is the limiting reagent.

We convert the mass to moles (mass / molar mass) → 10 g / 16 g/mol = 0.625 moles

According to stoichiometry, 1 mol of methane can produce 1 mol of CO₂. Therefore If we have 0.625 moles of CH₄ we produce 0.625 moles of CO₂. Ratio is 1:1.

Let's convert the moles to mass → (mol . molar mass) =

0.625 mol . 44 g/mol = 27.5 g

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Which of the following increases as you move up a column of the periodic table?

luda_lava [24]

Answer:

electronegativity increases

6 0

3 years ago

Draw the best Lewis structure for CH 3 -1. What is the formal charge on the C?

djyliett [7]

Answer : The formal charge on the C is, (-1) charge.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $CH_3^{-1}$

As we know that carbon has '4' valence electrons and hydrogen has '1' valence electron.

Therefore, the total number of valence electrons in $CH_3^{-1}$ = 4 + 3(1) + 1 = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

Now we have to determine the formal charge on carbon atom.

Formula for formal charge :

$\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}$

$\text{Formal charge on C}=4-2-\frac{6}{2}=-1$

The formal charge on the C is, (-1) charge.

3 0

3 years ago

Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el

LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>

8 0

3 years ago

What is the net ionic equation for the reaction if any that occurs when aqueous solutions of Na2CO3 and HCL are mixed?

strojnjashka [21]

Answer:

CO₃²⁻(aq) + 2H⁺(aq) → CO₂ (g) + H₂O (l)

Explanation:

The balanced reaction between Na2CO3 and HCl is given as;

Na₂CO₃ (aq) + 2 HCl (aq) → 2 NaCl (aq) + CO₂ (g) + H₂O (l)

The next step is o express the species as ions.

The complete ionic equation for the above reaction would be;

2Na⁺(aq) + CO₃²⁻(aq) + 2H⁺(aq) + 2Cl⁻(aq) → Na⁺(aq) + Cl⁻(aq) + CO₂ (g) + H₂O (l)

The next step is to cancel out the spectator ion ions; that is the ions that appear in both the reactant and product side unchanged.

The spectator ions are; Na⁺ and Cl⁻

The net ionic equation is given as;

CO₃²⁻(aq) + 2H⁺(aq) → CO₂ (g) + H₂O (l)

7 0

3 years ago

Why the enthalpy of Ba(oh)2 +h2so4 is greater than Ba(oh)2 + hcl?

Rina8888 [55]

Answer:

Explanation:

To break apart a molecule of H2So4 is much higher than HCl although HCl is an ionic bond it is only bonded to one hydrogen. While H2So4 is bonded to two of them, aswell as its structure being much more complex. The energy to break Ba(h)2 is equal in both.

4 0

2 years ago