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asambeis [7]
4 years ago
13

How much CO2 is produced from 10g of CH4?

Chemistry
1 answer:
prohojiy [21]4 years ago
3 0

Answer:

0.625 moles of CO₂ can be produced by this reaction.

27.5 g of CO₂

Explanation:

A reaction where CO₂ can be produced is combustion.

The reactants are methane (in this case) and oxygen, while the products will be CO₂ and  H₂O.

The balanced reaction is: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

We assume the oxygen is in excess, so the methane gas, is the limiting reagent.

We convert the mass to moles (mass / molar mass) → 10 g / 16 g/mol = 0.625 moles

According to stoichiometry, 1 mol of methane can produce 1 mol of CO₂. Therefore If we have 0.625 moles of CH₄ we produce 0.625 moles of CO₂. Ratio is 1:1.

Let's convert the moles to mass → (mol . molar mass) =

0.625 mol . 44 g/mol = 27.5 g

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The  mass  of water formed  is


<u><em>calculation</em></u>

Use  the  ideal   gas  equation   to  calculate the  moles of  NH3  and O2

that  is  Pv= n RT

where;  P= pressure,  

V=  volume,

n = number  of  moles,

R=gas   constant  = 0.0821  l .atm/ mol.K

make n the formula of  the subject  by diving   both side  by  RT

n =  PV /RT

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n= (1.50 atm  x 12.5 L) /(  0.0821 L. atm /mol.k   x 298 K)  =0.766  moles

The  moles  of  O2

=(1.1 atm  x 18.9  L) /  (  0.0821 L. atm/ mol.k   x 323 K) = 0.784  moles


write the reaction  between  NH3  and  O2

4 NH3  + 5 O2  →4 No  +6H2O


from  equation above  0.766  moles of NH3  reacted to produce  

0.766 x 6/4 =1.149 moles of H2O


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since  O2  is totally  consumed, O2  is the limiting  reagent  and therefore  the  moles of H2O  produced=  0.9408  moles


mass  of  H2O  = moles x molar mass

 from  periodic table the  molar mass  of H2O  =  (1 x2)+16= 18  g/mol

mass = 18 g/mol  x 0.9408  moles= 16.93  grams


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