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sammy [17]
3 years ago
11

An equimolar mixture of X (g) and Y (g) is placed inside a rigid container at constant temperature. The particle diagram above r

epresents the changes that occur over time. Based on the particle
diagram, which of the following best predicts whether or not the system has reached equilibrium by 300 s?
a. It is not possible to determine that the system has reached equilibrium by 300 s because the stoichiometry of the reaction is not known.

b. it is not possible to determine that the system has reached equilibrium by 300 s because the amounts of X, Y, and XY have continued to change

c. The system has reached equilibrium by 300 s because the rate of formation of XY is constant
d. The system has reached equilibrium by 300 s because the rates of consumption of X and Y are equal

Chemistry
1 answer:
iris [78.8K]3 years ago
6 0

Answer:

B

Explanation:

t= 300s has more XY than t=200s, which means that it continues to change

*i think

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What mass (g) of barium iodide is contained in 188 ml of a barium iodide solution that has an iodide ion concentration of 0.532m
Katarina [22]

Answer:

What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?

A) 19.6

B) 39.1

C) 19,600

D) 39,100

E) 276

The correct answer to the question is

B) 39.1  grams

Explanation:

To solve the question

The molarity ratio is given by

188 ml of 0.532 M solution of iodide.

Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles

To find the mass, we note that the Number of moles = \frac{Mass}{Molar Mass} from which we have

Mass = Number of moles × molar mass

Where the molar mass of Barium Iodide = 391.136 g/mol

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8 0
2 years ago
Consider the following reaction 2 N2O(g) => 2 N2(g) + O2(g) rate = k[N2O]. For an initial concentration of N2O of 0.50 M, cal
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Answer:

After 2.0 minutes the concentration of N2O is 0.3325 M

Explanation:

Step 1: Data given

rate = k[N2O]

initial concentration of N2O of 0.50 M

k = 3.4 * 10^-3/s

Step 2: The balanced equation

2N2O(g) → 2 N2(g) + O2(g)  

Step 3: Calculate the concentration of N2O after 2.0 minutes

We use the rate law to derive a time dependent equation.

-d[N2O]/dt = k[N2O]

ln[N2O] = -kt + ln[N2O]i

 ⇒ with k = 3.4 *10^-3 /s

⇒ with t = 2.0 minutes = 120s

⇒ with [N2O]i = initial conc of N2O = 0.50 M

ln[N2O] = -(3.4*10^-3/s)*(120s) + ln(0.5)

ln[N2O] = -1.101

e^(ln[N2O]) = e^(-1.1011)

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After 2.0 minutes the concentration of N2O is 0.3325 M

3 0
2 years ago
How can i make babies
Studentka2010 [4]

Answer with Explanation:

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Answer:

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Explanation:

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Does the application of heat to a substance always produce a chemical change?
tatiyna

Answer;

No, sometimes it just causes a physical change, such as ice melting to water.

Explanation;

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Heating a substance may cause a physical change or a chemical change.  For example melting ice to water, involves supplying heat to change ice into water which is a chemical change.

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