Answer:
470 N.
Explanation:
Using equations of motion:
S = vi*t + 1/2*(a*(t^2))
Given:
S = 0.65 m
t = 1.5 s
vi = 0 m/s
0.65 = 1/2 * (a * (1.5)^2)
a = 1.3/2.25
= 0.578 m/s^2
Force = mass * acceleration due to gravity
= 92 * 0.578
= 53.16 N
Total force = 420 + 53.16
= 473.16 N
= 470 N.
B, C. Also literally a quick search yielded these results, roughly half the time to type this out.
The coordinates are- <span>RA 19° 24' 0" | Dec 59° 0.000'
It is located in the asteroid belt between mars and jupiter :)
</span><span>
</span>
Answer:
8 signals received by twin A during the trip.
Explanation:
Given that,
Distance = 12 light year
Speed = 0.6 c
Time = 1 year
We need to calculate the time by A
Using formula of time
![T=t\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}](https://tex.z-dn.net/?f=T%3Dt%5Csqrt%7B%5Cdfrac%7B1%2B%5Cdfrac%7Bv%7D%7Bc%7D%7D%7B1-%5Cdfrac%7Bv%7D%7Bc%7D%7D%7D)
Put the value into the formula
![T=1\sqrt{\dfrac{1+0.6}{1-0.6}}](https://tex.z-dn.net/?f=T%3D1%5Csqrt%7B%5Cdfrac%7B1%2B0.6%7D%7B1-0.6%7D%7D)
![T=2\ years](https://tex.z-dn.net/?f=T%3D2%5C%20years)
Similarly,
The expression for distance cover by A
![D=d\sqrt{1-\dfrac{v^2}{c^2}}](https://tex.z-dn.net/?f=D%3Dd%5Csqrt%7B1-%5Cdfrac%7Bv%5E2%7D%7Bc%5E2%7D%7D)
![D=12\sqrt{1-(0.6)^2}](https://tex.z-dn.net/?f=D%3D12%5Csqrt%7B1-%280.6%29%5E2%7D)
![D=9.6\ ly](https://tex.z-dn.net/?f=D%3D9.6%5C%20ly)
We need to calculate the time
Using formula of time
![t=\dfrac{D}{v}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7BD%7D%7Bv%7D)
![t=\dfrac{9.6}{0.6}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B9.6%7D%7B0.6%7D)
![t=16\ years](https://tex.z-dn.net/?f=t%3D16%5C%20years)
We need to calculate the signals received by twin A
Using formula for number of signals
![n=\dfrac{t}{T}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7Bt%7D%7BT%7D)
Put the value into the formula
![n=\dfrac{16}{2}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B16%7D%7B2%7D)
![n=8\ signals](https://tex.z-dn.net/?f=n%3D8%5C%20signals)
Hence, 8 signals received by twin A during the trip.