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2 years ago

How does the width of the visible spectrum compared to that of the entire electromagnetic spectrum?

1 answer:

Citrus2011 [14]2 years ago

5 0

<span>The width of the physical spectrum is shorter than that of the electromagnetic spectrum. The visible spectrum is the light that can be seen with the human eye, which we see as the colors red, orange, yellow, green, blue, indigo, and violet or ROY G. BIV. However, there are more wavelengths that can be seen beyond that, which are apart of the electromagnetic spectrum. For example, the UV rays, microwaves, and Gamma Rays cannot be seen by the human eye. Therefore, the electromagnetic spectrum is longer than the visible spectrum because there is so much more that humans can not see. The visible spectrum is only 400-750nm. The electromagnetic spectrum is 10 to the -14 to 10 to the 4 meters.</span>

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What is the acceleration of a car that moves at a steady velocity of 100 km/h for 100 seconds? Explain your answer.

RUDIKE [14]

Answer:

a = 0 m/s²

Explanation:

given,

car moving at steady velocity = 100 Km/h

1 km/h = 0.278 m/s

100 Km/h = 27.8 m/s

time of acceleration = 100 s

acceleration is equal to change in velocity per unit time.

$a=\dfrac{dv}{dt}$

change in velocity of the car is 27.8 - 27.8 = 0

$a=\dfrac{0}{100}$

a = 0 m/s²

If the car is moving with steady velocity then acceleration of the car is zero.

Hence, the acceleration of the car is equal to a = 0 m/s²

3 0

3 years ago

Whenever two Apollo astronauts were on the surface of the Moon, a third astronaut orbited the Moon. Assume the orbit to be circu

inysia [295]

Answer:

$v = 1,582 \ \frac{m}{s}$

Explanation:

We know that for circular motion the centripetal acceleration $a_c$ is:

$a_c = \frac{v^2}{r}$

where v is the speed and r is the radius.

The centripetal acceleration for the astronaut must be the gravitational acceleration due to the gravity, as there are no other force. So

$a_c = 1.27 \frac{m}{s^2}$ .

The radius of the orbit must be the radius of the Moon, plus the 270 km above the surface

$r = 1.7 * 10^6 \ m + 270 \ km$

$r = 1.7 * 10^6 \ m + 270 * 10^3 \ m$

$r = 1.7 * 10^6 \ m + 0.270 * 10^6 \ m$

$r = 1.97 * 10^6 \ m$

We can obtain the speed as:

$v^2 = a_c r$

$v = \sqrt{a_c r}$

$v = \sqrt{1.27 \frac{m}{s^2} * 1.97 * 10^6 \ m}$

$v = \sqrt{ 2.509 \ 10^6 \ \frac{m^2}{s^2}}$

$v = 1.582 \ 10^3 \ \frac{m}{s}$

$v = 1,582 \ \frac{m}{s}$

And this is the orbital speed.

7 0

3 years ago

Why are Murcury, venus, earth and mars called the "terrestrial" planets?

Fittoniya [83]

Mercury, Venus, Earth, and Mars are considered terrestrial planets because those planets are mainly composed of metal or rock and are closest to the sun.

5 0

2 years ago

What would make oppositely charged objects attract each other more? increasing the positive charge of the positively charged obj

kykrilka [37]

Answer:

Explanation:

I did the test :D

3 0

2 years ago

Read 2 more answers

A heat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. The same engine

Goryan [66]

Answer:

a) 2.85 kW

b) $ 432

c) $ 76.95

Explanation:

Average price of electricity = 1 $/40 MJ

Q = 20 kW

Heat energy production = 20.0 KJ/s

Coefficient of performance, K = 7

also

K=(QH)/Win

Now,

Coefficient of Performance, K = (QH)/Win = (QH)/P(in) = 20/P(in) = 7

where

P(in) is the input power

Thus,

P(in) = 20/7 = 2.85 kW

b) Cost = Energy consumed × charges

Cost = ($1/40000kWh) × (16kW × 300 × 3600s)

cost = $ 432

c) cost = (1$/40000kWh) × (2.85 kW × 200 × 3600s) = $76.95

4 0

3 years ago