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2 years ago

How does the width of the visible spectrum compared to that of the entire electromagnetic spectrum?

1 answer:

Citrus2011 [14]2 years ago

5 0

<span>The width of the physical spectrum is shorter than that of the electromagnetic spectrum. The visible spectrum is the light that can be seen with the human eye, which we see as the colors red, orange, yellow, green, blue, indigo, and violet or ROY G. BIV. However, there are more wavelengths that can be seen beyond that, which are apart of the electromagnetic spectrum. For example, the UV rays, microwaves, and Gamma Rays cannot be seen by the human eye. Therefore, the electromagnetic spectrum is longer than the visible spectrum because there is so much more that humans can not see. The visible spectrum is only 400-750nm. The electromagnetic spectrum is 10 to the -14 to 10 to the 4 meters.</span>

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You are playing a speed-based card game with your 64-year-old grandfather. The object of the game is to get rid of your cards as

Masteriza [31]

Now, you always beat him. Your grandfather is likely experiencing a slight decline in perceptual speed.

<u>Explanation:</u>

The speed of perception refers to the capacity to accurately (and completely) compare words letter, digits, objects, images, etc. When testing, these objects can be displayed simultaneously or one after the other. This type of test can be included in the proficiency test.

For example, we have also seen all the puzzles that ask the reader to notice the differences between the two pictures. The time it takes to recognize these differences is a measure of the speed of perception. Likewise, in getting rid of cards at the given situation, grandfather experiences a less decline in his perceptual speed.

4 0

3 years ago

The diagram shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 3.6 N and the angl

Nuetrik [128]

<h3>Answer</h3>

6.6 N pointing to the right

<h3>Explanation</h3>

Given that,

two forces acting of magnitude 3.6N

angle between them = 48°

To find,

the third force that will cause the object to be in equilibrium

Find the vertical and horizontal components of the two forces

vertical force1 = sin(24)(3.6)

vertical force2= -sin(24)(3.6)

<em>(negative sign since it is acting on opposite direction)</em>

vertical force3 = sin(24)(3.6) - sin(24)(3.6)

= 0

horizontal force1 = cos(24)(3.6)

horizontal force2= cos(24)(3.6)

horizontal force3 = cos(24)(3.6) + cos(24)(3.6)

= 2(cos(24)(3.6))

= 6.5775 N

≈ 6.6 N

<em />

4 0

3 years ago

While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of bloo

Sergio [31]

Answer:

m≈501.57 g

Explanation:

The density formula is:

d=m/v

Let’s rearrange the formula for m. m is being divided by v. The inverse of division is multiplication, so multiply both aides by v.

d*v= m/v*v

d*v=m

The mass can be found by multiply the density and the volume.

m=d*v

The density is 1.06 grams per milliliter and the volume is 473.176 milliliters.

d= 1.06 g/mL

v= 473.176 mL

Substitute the values into the formula.

m= 1.06 g/mL * 473.176 mL

Multiply. When multiplying, the mL will cancel out.

m= 501.56656 g

Let’s round to the nearest hundredth. The 6 in the thousandth place tells us to round the 6 to a 7 in the hundredth place.

m ≈501.57 g

The mass is about 501.57 grams.

7 0

2 years ago

Read 2 more answers

Atom in the ground state is said to be

koban [17]

Answer:

Ground-state atom

Explanation:

When an atom is not excited, it is in its ground-state, which we refer as "standard" or "normal" state.

(Hopefully that helped you!)

GOOD LUCK

Astrophysicist Dr. D

3 0

3 years ago

Two stationary positive point charges, charge 1 of magnitude 3.90 nC and charge 2 of magnitude 1.80 nC, are separated by a dista

soldi70 [24.7K]

Answer:

$v = 7793150 m/s$

Explanation:

First, we are going to calculate the electrical potential in the point middle between the two charges

Remember that the electrical potential can be calculated as:

$v = \frac{kQ}{r}$

Where $k = 8.9874 x 10^{9} \frac{Nm^{2} }{C^{2} }$

and it is satisfy the superposition principle, thus

$v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.23} + \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.23}$

$v = 222.73v$

The electrical potential at 10 cm from charge 1 is:

$v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.1} + \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.36}$

$v = 395.44 v$

Since the work - energy theorem, we have:

$q\Delta v = \frac{mv^{2} }{2}$

where q is the electron's charge and m is the electron's mass

Therefore:

$v = \sqrt{\frac{2q\Delta v}{m} }$

$v = 7793150 m/s$

6 0

2 years ago