How does the width of the visible spectrum compared to that of the entire electromagnetic spectrum?

1 answer:

Citrus2011 [14]3 years ago

5 0

The width of the physical spectrum is shorter than that of the electromagnetic spectrum. The visible spectrum is the light that can be seen with the human eye, which we see as the colors red, orange, yellow, green, blue, indigo, and violet or ROY G. BIV. However, there are more wavelengths that can be seen beyond that, which are apart of the electromagnetic spectrum. For example, the UV rays, microwaves, and Gamma Rays cannot be seen by the human eye. Therefore, the electromagnetic spectrum is longer than the visible spectrum because there is so much more that humans can not see. The visible spectrum is only 400-750nm. The electromagnetic spectrum is 10 to the -14 to 10 to the 4 meters.

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A reaction has a rate constant of 0.0117 s-1 at 400.0 k and 0.689 s-1 at 450.0 k. calculate the activation energy in kilojoules

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By definition we have to:
LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
Where,
k1 = 0.0117 s-1
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Substituting
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answer
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Read 2 more answers

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ElenaW [278]

Answer:

The new kinetic energy would be 16 times greater than before.

Explanation:

Kinetic energy is found using this formula:

KE = 1/2mv²
where KE = kinetic energy (J), m = mass (kg), and v = velocity (m/s)

We can see that kinetic energy is directly proportional to the square of the velocity, meaning that if the speed was increased by 4 times, then the kinetic energy would get increased by a factor of 16.

The velocity just before the ball hits the ground can be found by the equation:

√(2gh)

Let's substitute h = 10 m and h = 40 m into this formula.

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We can see that the velocity increases by a factor of 4 (10 m → 40 m).

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Let us list out what we know from the question.

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