All categories

3 years ago

How do jellyfish reproduce..?

Chemistry

2 answers:

lesantik [10]3 years ago

7 0

Answer:

Jellyfish reproduction involves several different stages. In the adult, or medusa, stage of a jellyfish, they can reproduce sexually by releasing sperm and eggs into the water, forming a planula.

Explanation:

svp [43]3 years ago

5 0

Answer:

Jellyfish reproduction involves several different stages. In the adult, or medusa, stage of a jellyfish, they can reproduce sexually by releasing sperm and eggs into the water, forming a planula. ... The polyps clone themselves and bud, or strobilate, into another stage of jellyfish life, called ephyra.

Explanation: mark most brainliest pls

You might be interested in

The coefficient _____ is needed in front of HCl for the equation to be balanced.

Arte-miy333 [17]

$\huge{ANSWER}$

$\huge{2}$

6 0

3 years ago

Read 2 more answers

chemical properties a. include changes of state of a substance b. include mass and color c. include changes that alter the ident

8_murik_8 [283]

C. Include changes that alter the identity of a substance.

6 0

3 years ago

A sample of seawater weighs 250 g and has a volume of 173 ml. What is the density of seawater?

kari74 [83]

Answer:

<h2>The answer is 1.45 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass of seawater = 250 g

volume = 173 mL

It's density is

$density = \frac{250}{173} \\ = 1.4450867052...$

We have the final answer as

Hope this helps you

8 0

3 years ago

. What is the first element on the periodic table?

melamori03 [73]

Answer:

The first element in the periodic table is hydrogen.

Explanation:

Hydrogen has an atomic number of one, making it the first element of the periodic table. The atomic number of an element is just the number of protons in the nucleus, so hydrogen has one proton. The neutrons and electrons do not affect the atomic number. After hydrogen with one proton comes helium with two, lithium with three, beryllium with four, and so on.

6 0

3 years ago

Consider the reaction 2CO * O2 —> 2 CO2 what is the percent yield of carbon dioxide (MW= 44g/mol) of the reaction of 10g of c

Arturiano [62]

Answer:

Y = 62.5%

Explanation:

Hello there!

In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

$m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO} *\frac{44gCO_2}{1molCO_2}\\\\ m_{CO_2}^{theoretical}=16gCO_2$

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

$Y=\frac{10g}{16g} *100\%\\\\Y=62.5\%$

Best regards!

8 0

3 years ago