if the pressure in a balloon is 20 atm at 20 K, what will be the pressure when the temperature is raised to 30K?
1 answer:
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Answer: 77.4 mL
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is:
where,
= initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg
= final pressure of dry gas at STP = 760 mm Hg
= initial volume of dry gas = 85.0 mL
= final volume of dry gas at STP = ?
= initial temperature of dry gas =
= final temperature of dry gas at STP =
Now put all the given values in the above equation, we get the final volume of wet gas at STP
Volume of dry gas at STP is 77.4 mL.