An object of known mass M with speed v0 travels toward a wall. The object collides with it and bounces away from the wall in the
opposite direction in which the object was initially traveling. The wall exerts an average force F0 on the object during the collision. A student must use the equation Δp⃗ =F⃗ Δt to determine the change in momentum of the object from immediately before the collision to immediately after the collision. Which side of the equation could the student use to determine the change of the object's momentum?
2 answers:
You might be interested in
Answer:
Speed = 0.00392 m/s
Explanation:
Solution:
Frequency of the radio = 85 MHz
If we have the frequency, we can calculate the wavelength of the radio wave.
As we know,
Frequency = speed of light/wavelength
wavelength = c/f
c = speed of light = 3 x m/s
So,
Wavelength = 3 x m/s / 85 x
Hz
Wavelength = 3.5294 m
Man gets disturbed reception at t = 15 min
t = 15 x 60 = 900 s
t = 900 s
Speed = distance/time
Here, distance is wavelength. So,
Speed = 3.5294 m / 900 s
Speed = 0.00392 m/s
Hence, the man's car is going with speed of 0.00392 m/s
Taking into account the definition of density, the volume of the metal block is 3 m³.
<h3>What is density</h3>Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.
<h3>Volume of the metal block</h3>In this case, you know that:
- Density= 5000
- Mass= 15000 kg
- Volume= ?
Replacing in the definition of density:
Solving:
volume×5000 = 15000 kg
volume=
<u><em>volume= 3 m³</em></u>
In summary, the volume of the metal block is 3 m³.
Learn more about density:
#SPJ12
Answer:
Explanation:
We have this concentration in units of :
And we need to express it in , knowing:
Hence: