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3 years ago

A double replacement reaction can be best described as a reaction in which

Chemistry

1 answer:

ExtremeBDS [4]3 years ago

3 0

<h3>Answer </h3>

Option C= ions are exchanged between two compounds.

<h3>Explanation </h3>

A double displacement reaction, also known as a double replacement reaction or metathesis, is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products. For example,

Na2S + 2HCl → H2S + 2NaCl

Option D is incorrect because electrons are exchanged between the atoms in oxidation –reduction reactions.

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Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o

vivado [14]

<u>Answer:</u>

<u>For 1:</u> The amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

<u>For 2:</u> The amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

<u>Explanation:</u>

<u>For 1:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of $KIO_3$ solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

$0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol$

Hence, the amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

<u>For 2:</u>

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

$2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3$

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = $\frac{1}{2}\times 0.00025=0.000125mol$ of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

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3 years ago

A certain liquid sample has a volume of 14.7 mL and a mass of 22.8 grams. Calculate the density.

ira [324]

M = 22.8 g
V = 14.7 mL
ρ - ?

ρ = m/V
ρ = 22.8/14.7 = 1.55 g/mL

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The answer is b. 5 units

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A solution in which more solute can be dissolved is called a(n) ???? solution

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