Answer:
i think the answer is Continental polar air masses
Explanation:
Answer:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
Explanation:
H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)
A careful observation of the equation above, shows that the equation is already balanced.
To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
Oxygen had 6 valence electrons
KOH -------> K+ OH-
Ba(OH)2 ------> Ba+2. 2OH-
Answer:
The answer to your question is: letter E
Explanation:
A. This option is correct, the n = 3 shell only has subshells: s, p and d, and shell n = 4 or 5 have f subshell.
B. This option is true in subshell p could be at most 6 electrons and 3 suborbitals.
C. This option is correct orbital "s" is a sphere.
D. This option is correct, in subshell d could be at most 10 electrons and 5 orbitals.
E. This option is false, hydrogen only has 1 electron and then one subshell (s).
