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alexandr402 [8]
3 years ago
9

Conservation of mass to balance the following reaction. Na2S+ KI= NaI+ K2S

Chemistry
1 answer:
lesantik [10]3 years ago
5 0

Answer:

1+2=2+1 is the answer for the question

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The oxidation of copper(I) oxide, Cu 2 O ( s ) , to copper(II) oxide, CuO ( s ) , is an exothermic process. 2 Cu 2 O ( s ) + O 2
ICE Princess25 [194]

Answer:

The energy released as heat when 9.94 g Cu 2 O ( s ) undergo oxidation at constant pressure is -10.142 kJ

Explanation:

Here we have

2Cu₂O ( s ) + O₂ ( g ) ⟶ 4 CuO ( s ) Δ H ∘ rxn = − 292.0 kJ mol

In the above reaction, 2 Moles of Cu₂O (copper (I) oxide) react with one mole of O₂ to produce 4 moles of CuO, with the release of − 292.0 kJ/mol of energy

Therefore,

1 Moles of Cu₂O (copper (I) oxide) react with 0.5 mole of O₂ to produce 2 moles of CuO, with the release of − 146.0 kJ  of energy

We have 9.94 g of Cu₂O with molar mass given as 143.09 g/mol

Hence the number of moles in 9.94 g of Cu₂O is given as

9.94/143.09 = 6.95 × 10⁻² moles of Cu₂O

6.95 × 10⁻² moles of Cu₂O will therefore produce 6.95 × 10⁻² ×  − 146.0 kJ mol  or -10.142 kJ.

3 0
3 years ago
Convert 3841 cL to L. SHOW WORK PLS
barxatty [35]

Answer:

1 cl = 1 * 10-5 m³

1 L = 1 * 10-3 m³

1 L = 0.001 m³

1 m³ = (1/0.001) L

1 m³ = 1000 L

1 cl = 1 * 10-5 * 1000 L

1 cl = 0.01 L

4 0
2 years ago
The unheated Gas in the above system has a volume of 20.0 L at a temperature of 25.0 C and a pressure of 1.00 atm. The gas is he
kipiarov [429]

Answer:

1.25 atm.

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 20L

Initial temperature (T1) = 25°C

Initial pressure = 1 atm

Final temperature (T2) = 100°C

Final volume (V2) = constant i.e remain the same

Final pressure (P2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below:

Temperature (Kelvin) = temperature (celsius) + 273

Initial temperature (T1) = 25°C = 25°C + 273 = 298K

Final temperature (T2) = 100°C = 100°C + 273 = 373K

Step 3:

Determination of the final pressure of the gas. This is illustrated below:

Since the volume is constant, the following equation, P1/T1 = P2/T2 will be used to obtain the final pressure of gas as follow:

P1/T1 = P2/T2

Initial temperature (T1) = 298k

Initial pressure = 1 atm

Final temperature (T2) = 373K

Final pressure (P2) =?

P1/T1 = P2/T2

1/298 = P2 /373

Cross multiply to express in linear form

298 x P2 = 1 x 373

Divide both side by 298

P2 = 373/298

P2 = 1.25 atm.

Therefore, the pressure of the heated gas is 1.25 atm.

3 0
3 years ago
An object with a mass of 15kg is accelerating at 10m/s2. What is the force carried by this object
sladkih [1.3K]

Answer: 150N

Explanation:

The formula to calculate the force will be the mass multiplied by the acceleration. In this case, mass = 15kg and acceleration = 10m/s². Therefore, force will be:

= Mass × Acceleration

= 15 × 10

= 150N

The force is 150Newton

8 0
3 years ago
33,792 ft = ? miles. can you help me please
konstantin123 [22]

Answer:

6.4 miles

Could you please give me brainliest, I need it.

Explanation:

7 0
3 years ago
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